Basic Math Examples

3 + | c - 1 | = 3

$3 + | c - 1 | = 3$

Step 1

Move all terms not containing

| c - 1 |

$| c - 1 |$ to the right side of the equation.

Tap for more steps...

Step 1.1

Subtract

3

$3$ from both sides of the equation.

| c - 1 | = 3 - 3

$| c - 1 | = 3 - 3$

Step 1.2

Subtract

3

$3$ from

3

$3$ .

| c - 1 | = 0

$| c - 1 | = 0$

| c - 1 | = 0

$| c - 1 | = 0$

Step 2

Remove the absolute value term. This creates a

\pm

$\pm$ on the right side of the equation because

| x | = \pm x

$| x | = \pm x$ .

c - 1 = \pm 0

$c - 1 = \pm 0$

Step 3

Plus or minus

0

$0$ is

0

$0$ .

c - 1 = 0

$c - 1 = 0$

Step 4

Add

1

$1$ to both sides of the equation.

c = 1

$c = 1$

Step 5

Remove the absolute value term. This creates a

\pm

$\pm$ on the right side of the equation because

| x | = \pm x

$| x | = \pm x$ .

c - 1 = \pm 0

$c - 1 = \pm 0$

Step 6

Plus or minus

0

$0$ is

0

$0$ .

c - 1 = 0

$c - 1 = 0$

Step 7

Add

1

$1$ to both sides of the equation.

c = 1

$c = 1$

⎡ ⎢ ⎣ \begin{matrix} x^{2} & \frac{1}{2} \sqrt{π} & \int x d x \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$