Basic Math Examples

$\frac{8 p^{3} + 1}{4 p^{3} + 20 p^{2} - p - 5}$

Step 1

Simplify the numerator.

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Step 1.1

Rewrite $8 p^{3}$ as ${(2 p)}^{3}$ .

$\frac{{(2 p)}^{3} + 1}{4 p^{3} + 20 p^{2} - p - 5}$

Step 1.2

Rewrite $1$ as $1^{3}$ .

$\frac{{(2 p)}^{3} + 1^{3}}{4 p^{3} + 20 p^{2} - p - 5}$

Step 1.3

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = 2 p$ and $b = 1$ .

$\frac{(2 p + 1) ({(2 p)}^{2} - (2 p) \cdot 1 + 1^{2})}{4 p^{3} + 20 p^{2} - p - 5}$

Step 1.4

Simplify.

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Step 1.4.1

Apply the product rule to $2 p$ .

$\frac{(2 p + 1) (2^{2} p^{2} - (2 p) \cdot 1 + 1^{2})}{4 p^{3} + 20 p^{2} - p - 5}$

Step 1.4.2

Raise $2$ to the power of $2$ .

$\frac{(2 p + 1) (4 p^{2} - (2 p) \cdot 1 + 1^{2})}{4 p^{3} + 20 p^{2} - p - 5}$

Step 1.4.3

Multiply $2$ by $- 1$ .

$\frac{(2 p + 1) (4 p^{2} - 2 p \cdot 1 + 1^{2})}{4 p^{3} + 20 p^{2} - p - 5}$

Step 1.4.4

Multiply $- 2$ by $1$ .

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1^{2})}{4 p^{3} + 20 p^{2} - p - 5}$

Step 1.4.5

One to any power is one.

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1)}{4 p^{3} + 20 p^{2} - p - 5}$

Step 2

Simplify the denominator.

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Step 2.1

Factor out the greatest common factor from each group.

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Step 2.1.1

Group the first two terms and the last two terms.

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1)}{(4 p^{3} + 20 p^{2}) - p - 5}$

Step 2.1.2

Factor out the greatest common factor (GCF) from each group.

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1)}{4 p^{2} (p + 5) - (p + 5)}$

Step 2.2

Factor the polynomial by factoring out the greatest common factor, $p + 5$ .

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1)}{(p + 5) (4 p^{2} - 1)}$

Step 2.3

Rewrite $4 p^{2}$ as ${(2 p)}^{2}$ .

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1)}{(p + 5) ({(2 p)}^{2} - 1)}$

Step 2.4

Rewrite $1$ as $1^{2}$ .

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1)}{(p + 5) ({(2 p)}^{2} - 1^{2})}$

Step 2.5

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 2 p$ and $b = 1$ .

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1)}{(p + 5) (2 p + 1) (2 p - 1)}$

Step 3

Cancel the common factor of $2 p + 1$ .

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Step 3.1

Cancel the common factor.

$\frac{(2 p + 1) (4 p^{2} - 2 p + 1)}{(p + 5) (2 p + 1) (2 p - 1)}$

Step 3.2

Rewrite the expression.

$\frac{4 p^{2} - 2 p + 1}{(p + 5) (2 p - 1)}$