Basic Math Examples

60 \cdot 2.5

$60 \cdot 2.5$

Step 1

Multiply using long multiplication.

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Step 1.1

Multiply

$5$ by

$0$ . Place the result in the next column in the result line. There is one result line for each digit in

$2.5$ .


	$6$	$0$
$⨯$	$2$	. $5$
		$0$

Step 1.2

Multiply

$5$ by

$6$ . Place the ones digit

$(0)$ in the result line and carry the tens digit

$(3)$ . There is one result line for each digit in

$2.5$ .


	$6$	$0$
$⨯$	$2$	. $5$
$3$	$0$	$0$

Step 1.3

Multiply

$2$ by

$0$ . Place the result in the next column in the result line. There is one result line for each digit in

$2.5$ .


	$6$	$0$
$⨯$	$2$	. $5$
$3$	$0$	$0$
	$0$

Step 1.4

Multiply

$2$ by

$6$ . Place the ones digit

$(2)$ in the result line and carry the tens digit

$(1)$ . There is one result line for each digit in

$2.5$ .


		$6$	$0$
	$⨯$	$2$	. $5$
	$3$	$0$	$0$
$1$	$2$	$0$

Step 1.5

Add the numbers in each column. In this case, add

$0 + 0$ , then place the

$0$ in the result line.


		$6$	$0$
	$⨯$	$2$	. $5$
	$3$	$0$	$0$
$1$	$2$	$0$
			$0$

Step 1.6

Add the numbers in each column. In this case, add

$0 + 0$ , then place the

$0$ in the result line.


		$6$	$0$
	$⨯$	$2$	. $5$
	$3$	$0$	$0$
$1$	$2$	$0$
		$0$	$0$

Step 1.7

Add the numbers in each column. In this case, add

$3 + 2$ , then place the

$5$ in the result line.


		$6$	$0$
	$⨯$	$2$	. $5$
	$3$	$0$	$0$
$1$	$2$	$0$
	$5$	$0$	$0$

Step 1.8

Add the numbers in each column. In this case, add

$0 + 1$ , then place the

$1$ in the result line.


		$6$	$0$
	$⨯$	$2$	. $5$
	$3$	$0$	$0$
$1$	$2$	$0$
$1$	$5$	$0$	$0$


		$6$	$0$
	$⨯$	$2$	. $5$
	$3$	$0$	$0$
$1$	$2$	$0$
$1$	$5$	$0$	$0$

Step 2

To find the number of decimal places needed in the answer, add the number of decimal places in the multiplier and multiplicand. In this case, there is a total of

$1$ , so the answer must have

$1$ decimal places as well.

$150$