Algebra Examples

${(\frac{1}{2})}^{- x} = 1.6$

Step 1

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln ({(\frac{1}{2})}^{- x}) = \ln (1.6)$

Step 2

Expand the left side.

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Step 2.1

Expand $\ln ({(\frac{1}{2})}^{- x})$ by moving $- x$ outside the logarithm.

$- x \ln (\frac{1}{2}) = \ln (1.6)$

Step 2.2

Rewrite $\ln (\frac{1}{2})$ as $\ln (1) - \ln (2)$ .

$- x (\ln (1) - \ln (2)) = \ln (1.6)$

Step 2.3

The natural logarithm of $1$ is $0$ .

$- x (0 - \ln (2)) = \ln (1.6)$

Step 2.4

Subtract $\ln (2)$ from $0$ .

$- x (- \ln (2)) = \ln (1.6)$

Step 3

Simplify the left side.

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Step 3.1

Multiply $- x (- \ln (2))$ .

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Step 3.1.1

Multiply $- 1$ by $- 1$ .

$1 x \ln (2) = \ln (1.6)$

Step 3.1.2

Multiply $x$ by $1$ .

$x \ln (2) = \ln (1.6)$

Step 4

Divide each term in $x \ln (2) = \ln (1.6)$ by $\ln (2)$ and simplify.

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Step 4.1

Divide each term in $x \ln (2) = \ln (1.6)$ by $\ln (2)$ .

$\frac{x \ln (2)}{\ln (2)} = \frac{\ln (1.6)}{\ln (2)}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $\ln (2)$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{x \ln (2)}{\ln (2)} = \frac{\ln (1.6)}{\ln (2)}$

Step 4.2.1.2

Divide $x$ by $1$ .

$x = \frac{\ln (1.6)}{\ln (2)}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \frac{\ln (1.6)}{\ln (2)}$

Decimal Form:

$x = 0.67807190 \dots$