Algebra Examples

$x + y = 15$ $4 x + 4 y = 10$

Step 1

Subtract $y$ from both sides of the equation.

$x = 15 - y$

$4 x + 4 y = 10$

Step 2

Replace all occurrences of $x$ with $15 - y$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $4 x + 4 y = 10$ with $15 - y$ .

$4 (15 - y) + 4 y = 10$

$x = 15 - y$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $4 (15 - y) + 4 y$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$4 \cdot 15 + 4 (- y) + 4 y = 10$

$x = 15 - y$

Step 2.2.1.1.2

Multiply $4$ by $15$ .

$60 + 4 (- y) + 4 y = 10$

$x = 15 - y$

Step 2.2.1.1.3

Multiply $- 1$ by $4$ .

$60 - 4 y + 4 y = 10$

$x = 15 - y$

$60 - 4 y + 4 y = 10$

$x = 15 - y$

Step 2.2.1.2

Combine the opposite terms in $60 - 4 y + 4 y$ .

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Step 2.2.1.2.1

Add $- 4 y$ and $4 y$ .

$60 + 0 = 10$

$x = 15 - y$

Step 2.2.1.2.2

Add $60$ and $0$ .

$60 = 10$

$x = 15 - y$

$60 = 10$

$x = 15 - y$

$60 = 10$

$x = 15 - y$

$60 = 10$

$x = 15 - y$

$60 = 10$

$x = 15 - y$

Step 3

Since $60 = 10$ is not true, there is no solution.

No solution

Step 4