Algebra Examples

$3 x - 18 y + 6 z = 7$ $7 x - 2 y + z = 1$ $- x + 6 y - 2 z = - 2$

Step 1

Move all terms not containing $z$ to the right side of the equation.

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Step 1.1

Subtract $7 x$ from both sides of the equation.

$- 2 y + z = 1 - 7 x$

$3 x - 18 y + 6 z = 7$

$- x + 6 y - 2 z = - 2$

Step 1.2

Add $2 y$ to both sides of the equation.

$z = 1 - 7 x + 2 y$

$3 x - 18 y + 6 z = 7$

$- x + 6 y - 2 z = - 2$

$z = 1 - 7 x + 2 y$

$3 x - 18 y + 6 z = 7$

$- x + 6 y - 2 z = - 2$

Step 2

Replace all occurrences of $z$ with $1 - 7 x + 2 y$ in each equation.

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Step 2.1

Replace all occurrences of $z$ in $3 x - 18 y + 6 z = 7$ with $1 - 7 x + 2 y$ .

$3 x - 18 y + 6 (1 - 7 x + 2 y) = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $3 x - 18 y + 6 (1 - 7 x + 2 y)$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$3 x - 18 y + 6 \cdot 1 + 6 (- 7 x) + 6 (2 y) = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Multiply $6$ by $1$ .

$3 x - 18 y + 6 + 6 (- 7 x) + 6 (2 y) = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

Step 2.2.1.1.2.2

Multiply $- 7$ by $6$ .

$3 x - 18 y + 6 - 42 x + 6 (2 y) = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

Step 2.2.1.1.2.3

Multiply $2$ by $6$ .

$3 x - 18 y + 6 - 42 x + 12 y = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

$3 x - 18 y + 6 - 42 x + 12 y = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

$3 x - 18 y + 6 - 42 x + 12 y = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Subtract $42 x$ from $3 x$ .

$- 39 x - 18 y + 6 + 12 y = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

Step 2.2.1.2.2

Add $- 18 y$ and $12 y$ .

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 z = - 2$

Step 2.3

Replace all occurrences of $z$ in $- x + 6 y - 2 z = - 2$ with $1 - 7 x + 2 y$ .

$- x + 6 y - 2 (1 - 7 x + 2 y) = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $- x + 6 y - 2 (1 - 7 x + 2 y)$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Apply the distributive property.

$- x + 6 y - 2 \cdot 1 - 2 (- 7 x) - 2 (2 y) = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 2.4.1.1.2

Simplify.

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Step 2.4.1.1.2.1

Multiply $- 2$ by $1$ .

$- x + 6 y - 2 - 2 (- 7 x) - 2 (2 y) = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 2.4.1.1.2.2

Multiply $- 7$ by $- 2$ .

$- x + 6 y - 2 + 14 x - 2 (2 y) = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 2.4.1.1.2.3

Multiply $2$ by $- 2$ .

$- x + 6 y - 2 + 14 x - 4 y = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 + 14 x - 4 y = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$- x + 6 y - 2 + 14 x - 4 y = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 2.4.1.2

Simplify by adding terms.

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Step 2.4.1.2.1

Add $- x$ and $14 x$ .

$13 x + 6 y - 2 - 4 y = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 2.4.1.2.2

Subtract $4 y$ from $6 y$ .

$13 x + 2 y - 2 = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$13 x + 2 y - 2 = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$13 x + 2 y - 2 = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$13 x + 2 y - 2 = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$13 x + 2 y - 2 = - 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 3

Solve for $x$ in $13 x + 2 y - 2 = - 2$ .

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Step 3.1

Move all terms not containing $x$ to the right side of the equation.

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Step 3.1.1

Subtract $2 y$ from both sides of the equation.

$13 x - 2 = - 2 - 2 y$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 3.1.2

Add $2$ to both sides of the equation.

$13 x = - 2 - 2 y + 2$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 3.1.3

Combine the opposite terms in $- 2 - 2 y + 2$ .

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Step 3.1.3.1

Add $- 2$ and $2$ .

$13 x = - 2 y + 0$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 3.1.3.2

Add $- 2 y$ and $0$ .

$13 x = - 2 y$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$13 x = - 2 y$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$13 x = - 2 y$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 3.2

Divide each term in $13 x = - 2 y$ by $13$ and simplify.

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Step 3.2.1

Divide each term in $13 x = - 2 y$ by $13$ .

$\frac{13 x}{13} = \frac{- 2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $13$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{13 x}{13} = \frac{- 2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 3.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$x = \frac{- 2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$x = \frac{- 2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Move the negative in front of the fraction.

$x = - \frac{2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$x = - \frac{2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$x = - \frac{2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

$x = - \frac{2 y}{13}$

$- 39 x - 6 y + 6 = 7$

$z = 1 - 7 x + 2 y$

Step 4

Replace all occurrences of $x$ with $- \frac{2 y}{13}$ in each equation.

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Step 4.1

Replace all occurrences of $x$ in $- 39 x - 6 y + 6 = 7$ with $- \frac{2 y}{13}$ .

$- 39 (- \frac{2 y}{13}) - 6 y + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $- 39 (- \frac{2 y}{13}) - 6 y + 6$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Cancel the common factor of $13$ .

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Step 4.2.1.1.1.1

Move the leading negative in $- \frac{2 y}{13}$ into the numerator.

$- 39 \frac{- 2 y}{13} - 6 y + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

Step 4.2.1.1.1.2

Factor $13$ out of $- 39$ .

$13 (- 3) (\frac{- 2 y}{13}) - 6 y + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

Step 4.2.1.1.1.3

Cancel the common factor.

$13 \cdot (- 3 \frac{- 2 y}{13}) - 6 y + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

Step 4.2.1.1.1.4

Rewrite the expression.

$- 3 (- 2 y) - 6 y + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

$- 3 (- 2 y) - 6 y + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

Step 4.2.1.1.2

Multiply $- 2$ by $- 3$ .

$6 y - 6 y + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

$6 y - 6 y + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

Step 4.2.1.2

Simplify by adding terms.

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Step 4.2.1.2.1

Subtract $6 y$ from $6 y$ .

$0 + 6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

Step 4.2.1.2.2

Add $0$ and $6$ .

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 - 7 x + 2 y$

Step 4.3

Replace all occurrences of $x$ in $z = 1 - 7 x + 2 y$ with $- \frac{2 y}{13}$ .

$z = 1 - 7 (- \frac{2 y}{13}) + 2 y$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $1 - 7 (- \frac{2 y}{13}) + 2 y$ .

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Step 4.4.1.1

Multiply $- 7 (- \frac{2 y}{13})$ .

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Step 4.4.1.1.1

Multiply $- 1$ by $- 7$ .

$z = 1 + 7 (\frac{2 y}{13}) + 2 y$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.1.2

Combine $7$ and $\frac{2 y}{13}$ .

$z = 1 + \frac{7 (2 y)}{13} + 2 y$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.1.3

Multiply $2$ by $7$ .

$z = 1 + \frac{14 y}{13} + 2 y$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 + \frac{14 y}{13} + 2 y$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.2

To write $2 y$ as a fraction with a common denominator, multiply by $\frac{13}{13}$ .

$z = 1 + \frac{14 y}{13} + 2 y \cdot \frac{13}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.3

Simplify terms.

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Step 4.4.1.3.1

Combine $2 y$ and $\frac{13}{13}$ .

$z = 1 + \frac{14 y}{13} + \frac{2 y \cdot 13}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.3.2

Combine the numerators over the common denominator.

$z = 1 + \frac{14 y + 2 y \cdot 13}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 + \frac{14 y + 2 y \cdot 13}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.4

Simplify the numerator.

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Step 4.4.1.4.1

Factor $2 y$ out of $14 y + 2 y \cdot 13$ .

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Step 4.4.1.4.1.1

Factor $2 y$ out of $14 y$ .

$z = 1 + \frac{2 y (7) + 2 y \cdot 13}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.4.1.2

Factor $2 y$ out of $2 y \cdot 13$ .

$z = 1 + \frac{2 y (7) + 2 y (13)}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.4.1.3

Factor $2 y$ out of $2 y (7) + 2 y (13)$ .

$z = 1 + \frac{2 y (7 + 13)}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 + \frac{2 y (7 + 13)}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.4.2

Add $7$ and $13$ .

$z = 1 + \frac{2 y \cdot 20}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 4.4.1.4.3

Multiply $20$ by $2$ .

$z = 1 + \frac{40 y}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 + \frac{40 y}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 + \frac{40 y}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 + \frac{40 y}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

$z = 1 + \frac{40 y}{13}$

$6 = 7$

$x = - \frac{2 y}{13}$

Step 5

Since $6 = 7$ is not true, there is no solution.

No solution