기초 미적분 예제

$\frac{1}{1 + \log_{c} (a b)} + \frac{1}{1 + \log_{a} (b c)} + \frac{1}{1 + \log_{b} (c a)}$

단계 1

$\log_{c} (a b)$ 을 $\log_{c} (a) + \log_{c} (b)$ 로 바꿔 씁니다.

$\frac{1}{1 + \log_{c} (a) + \log_{c} (b)} + \frac{1}{1 + \log_{a} (b c)} + \frac{1}{1 + \log_{b} (c a)}$

단계 2

$\log_{a} (b c)$ 을 $\log_{a} (b) + \log_{a} (c)$ 로 바꿔 씁니다.

$\frac{1}{1 + \log_{c} (a) + \log_{c} (b)} + \frac{1}{1 + \log_{a} (b) + \log_{a} (c)} + \frac{1}{1 + \log_{b} (c a)}$

단계 3

$\log_{b} (c a)$ 을 $\log_{b} (c) + \log_{b} (a)$ 로 바꿔 씁니다.

$\frac{1}{1 + \log_{c} (a) + \log_{c} (b)} + \frac{1}{1 + \log_{a} (b) + \log_{a} (c)} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$

단계 4

공통 분모를 가지는 분수로 $\frac{1}{1 + \log_{c} (a) + \log_{c} (b)}$ 을 표현하기 위해 $\frac{1 + \log_{a} (b) + \log_{a} (c)}{1 + \log_{a} (b) + \log_{a} (c)}$ 을 곱합니다.

$\frac{1}{1 + \log_{c} (a) + \log_{c} (b)} \cdot \frac{1 + \log_{a} (b) + \log_{a} (c)}{1 + \log_{a} (b) + \log_{a} (c)} + \frac{1}{1 + \log_{a} (b) + \log_{a} (c)} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$

단계 5

공통 분모를 가지는 분수로 $\frac{1}{1 + \log_{a} (b) + \log_{a} (c)}$ 을 표현하기 위해 $\frac{1 + \log_{c} (a) + \log_{c} (b)}{1 + \log_{c} (a) + \log_{c} (b)}$ 을 곱합니다.

$\frac{1}{1 + \log_{c} (a) + \log_{c} (b)} \cdot \frac{1 + \log_{a} (b) + \log_{a} (c)}{1 + \log_{a} (b) + \log_{a} (c)} + \frac{1}{1 + \log_{a} (b) + \log_{a} (c)} \cdot \frac{1 + \log_{c} (a) + \log_{c} (b)}{1 + \log_{c} (a) + \log_{c} (b)} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$

단계 6

각 수식에 적절한 인수 $1$ 을 곱하여 수식의 분모가 모두 $(1 + \log_{c} (a) + \log_{c} (b)) (1 + \log_{a} (b) + \log_{a} (c))$ 이 되도록 식을 씁니다.

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단계 6.1

$\frac{1}{1 + \log_{c} (a) + \log_{c} (b)}$ 에 $\frac{1 + \log_{a} (b) + \log_{a} (c)}{1 + \log_{a} (b) + \log_{a} (c)}$ 을 곱합니다.

$\frac{1 + \log_{a} (b) + \log_{a} (c)}{(1 + \log_{c} (a) + \log_{c} (b)) (1 + \log_{a} (b) + \log_{a} (c))} + \frac{1}{1 + \log_{a} (b) + \log_{a} (c)} \cdot \frac{1 + \log_{c} (a) + \log_{c} (b)}{1 + \log_{c} (a) + \log_{c} (b)} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$

단계 6.2

$\frac{1}{1 + \log_{a} (b) + \log_{a} (c)}$ 에 $\frac{1 + \log_{c} (a) + \log_{c} (b)}{1 + \log_{c} (a) + \log_{c} (b)}$ 을 곱합니다.

$\frac{1 + \log_{a} (b) + \log_{a} (c)}{(1 + \log_{c} (a) + \log_{c} (b)) (1 + \log_{a} (b) + \log_{a} (c))} + \frac{1 + \log_{c} (a) + \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$

단계 6.3

$(1 + \log_{c} (a) + \log_{c} (b)) (1 + \log_{a} (b) + \log_{a} (c))$ 인수를 다시 정렬합니다.

$\frac{1 + \log_{a} (b) + \log_{a} (c)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))} + \frac{1 + \log_{c} (a) + \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$

단계 7

공통분모를 가진 분자끼리 묶습니다.

$\frac{1 + \log_{a} (b) + \log_{a} (c) + 1 + \log_{c} (a) + \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$

단계 8

$1$ 를 $1$ 에 더합니다.

$\frac{2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$

단계 9

공통 분모를 가지는 분수로 $\frac{2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}$ 을 표현하기 위해 $\frac{1 + \log_{b} (c) + \log_{b} (a)}{1 + \log_{b} (c) + \log_{b} (a)}$ 을 곱합니다.

단계 10

공통 분모를 가지는 분수로 $\frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$ 을 표현하기 위해 $\frac{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}$ 을 곱합니다.

$\frac{2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))} \cdot \frac{1 + \log_{b} (c) + \log_{b} (a)}{1 + \log_{b} (c) + \log_{b} (a)} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)} \cdot \frac{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 11

각 수식에 적절한 인수 $1$ 을 곱하여 수식의 분모가 모두 $(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))$ 이 되도록 식을 씁니다.

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단계 11.1

$\frac{2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}$ 에 $\frac{1 + \log_{b} (c) + \log_{b} (a)}{1 + \log_{b} (c) + \log_{b} (a)}$ 을 곱합니다.

$\frac{(2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))} + \frac{1}{1 + \log_{b} (c) + \log_{b} (a)} \cdot \frac{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 11.2

$\frac{1}{1 + \log_{b} (c) + \log_{b} (a)}$ 에 $\frac{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}$ 을 곱합니다.

$\frac{(2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))} + \frac{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{b} (c) + \log_{b} (a)) ((1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b)))}$

단계 11.3

$(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))$ 인수를 다시 정렬합니다.

$\frac{(2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))} + \frac{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{b} (c) + \log_{b} (a)) ((1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b)))}$

단계 11.4

$(1 + \log_{b} (c) + \log_{b} (a)) ((1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b)))$ 인수를 다시 정렬합니다.

$\frac{(2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))} + \frac{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 12

공통분모를 가진 분자끼리 묶습니다.

$\frac{(2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a)) + (1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13

분자를 간단히 합니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 13.1

첫 번째 수식의 항과 두 번째 수식의 항을 각각 곱하여 $(2 + \log_{a} (b) + \log_{a} (c) + \log_{c} (a) + \log_{c} (b)) (1 + \log_{b} (c) + \log_{b} (a))$ 를 전개합니다.

$\frac{2 \cdot 1 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) \cdot 1 + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) \cdot 1 + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) \cdot 1 + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) \cdot 1 + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + (1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.2

각 항을 간단히 합니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 13.2.1

$2$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) \cdot 1 + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) \cdot 1 + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) \cdot 1 + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) \cdot 1 + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + (1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.2.2

$\log_{a} (b)$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) \cdot 1 + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) \cdot 1 + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) \cdot 1 + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + (1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.2.3

$\log_{a} (c)$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) \cdot 1 + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) \cdot 1 + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + (1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.2.4

$\log_{c} (a)$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) \cdot 1 + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + (1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.2.5

$\log_{c} (b)$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + (1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.3

첫 번째 수식의 항과 두 번째 수식의 항을 각각 곱하여 $(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{c} (a) + \log_{c} (b))$ 를 전개합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 1 \cdot 1 + 1 \log_{c} (a) + 1 \log_{c} (b) + \log_{a} (b) \cdot 1 + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + \log_{a} (c) \cdot 1 + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.4

각 항을 간단히 합니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 13.4.1

$1$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 1 + 1 \log_{c} (a) + 1 \log_{c} (b) + \log_{a} (b) \cdot 1 + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + \log_{a} (c) \cdot 1 + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.4.2

$\log_{c} (a)$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 1 + \log_{c} (a) + 1 \log_{c} (b) + \log_{a} (b) \cdot 1 + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + \log_{a} (c) \cdot 1 + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.4.3

$\log_{c} (b)$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 1 + \log_{c} (a) + \log_{c} (b) + \log_{a} (b) \cdot 1 + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + \log_{a} (c) \cdot 1 + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.4.4

$\log_{a} (b)$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 1 + \log_{c} (a) + \log_{c} (b) + \log_{a} (b) + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + \log_{a} (c) \cdot 1 + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.4.5

$\log_{a} (c)$ 에 $1$ 을 곱합니다.

$\frac{2 + 2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 1 + \log_{c} (a) + \log_{c} (b) + \log_{a} (b) + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + \log_{a} (c) + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.5

$2$ 를 $1$ 에 더합니다.

$\frac{2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 3 + \log_{c} (a) + \log_{c} (b) + \log_{a} (b) + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + \log_{a} (c) + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.6

$\log_{a} (b)$ 를 $\log_{a} (b)$ 에 더합니다.

$\frac{2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 3 + \log_{c} (a) + \log_{c} (b) + 2 \log_{a} (b) + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + \log_{a} (c) + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.7

$\log_{a} (c)$ 를 $\log_{a} (c)$ 에 더합니다.

$\frac{2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 3 + \log_{c} (a) + \log_{c} (b) + 2 \log_{a} (b) + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + 2 \log_{a} (c) + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.8

$\log_{c} (a)$ 를 $\log_{c} (a)$ 에 더합니다.

$\frac{2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 3 + 2 \log_{c} (a) + \log_{c} (b) + 2 \log_{a} (b) + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + 2 \log_{a} (c) + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$

단계 13.9

$\log_{c} (b)$ 를 $\log_{c} (b)$ 에 더합니다.

$\frac{2 \log_{b} (c) + 2 \log_{b} (a) + \log_{a} (b) \log_{b} (c) + \log_{a} (b) \log_{b} (a) + \log_{a} (c) \log_{b} (c) + \log_{a} (c) \log_{b} (a) + \log_{c} (a) \log_{b} (c) + \log_{c} (a) \log_{b} (a) + \log_{c} (b) \log_{b} (c) + \log_{c} (b) \log_{b} (a) + 3 + 2 \log_{c} (a) + 2 \log_{c} (b) + 2 \log_{a} (b) + \log_{a} (b) \log_{c} (a) + \log_{a} (b) \log_{c} (b) + 2 \log_{a} (c) + \log_{a} (c) \log_{c} (a) + \log_{a} (c) \log_{c} (b)}{(1 + \log_{a} (b) + \log_{a} (c)) (1 + \log_{b} (c) + \log_{b} (a)) (1 + \log_{c} (a) + \log_{c} (b))}$