유한 수학 예제

$A = 4300 (1 + n \cdot 0.05)$ , $F V = \frac{603.42 ({(1 + 0.01)}^{4 n} - 1)}{0.01}$

단계 1

$A = 4300 (1 + n \cdot 0.05), F V = \frac{603.42 ({(1 + 0.01)}^{4 n} - 1)}{0.01}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$