유한 수학 예제

$[\begin{array}{c} 2 & - 1 & 5 \\ 0 & 3 & - 2 \end{array}] \cdot [\begin{array}{c} - 4 & 2 \\ 5 & 7 \end{array}]$

단계 1

$[\begin{array}{c} 2 & - 1 & 5 \\ 0 & 3 & - 2 \end{array}] \cdot [\begin{array}{c} - 4 & 2 \\ 5 & 7 \end{array}]$