유한 수학 예제

$[\begin{array}{c} 0 & 4 & - 2 \\ 1 & - 3 & 5 \end{array}] \cdot [\begin{array}{c} 2 & 1 \\ 3 & - 1 \end{array}]$

단계 1

$[\begin{array}{c} 0 & 4 & - 2 \\ 1 & - 3 & 5 \end{array}] \cdot [\begin{array}{c} 2 & 1 \\ 3 & - 1 \end{array}]$