유한 수학 예제

$[\begin{array}{c} 2 & - 1 \\ 6 & 0 \end{array}] \cdot [\begin{array}{c} - 4 & 0 \\ 3 & - 8 \\ - 7 & 0 \end{array}]$

단계 1

$[\begin{array}{c} 2 & - 1 \\ 6 & 0 \end{array}] \cdot [\begin{array}{c} - 4 & 0 \\ 3 & - 8 \\ - 7 & 0 \end{array}]$