예제

⎡ ⎢ ⎣ \begin{matrix} 4 & 4 & 0 2 & 3 & 1 1 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} 4 & 4 & 0 \\ 2 & 3 & 1 \\ 1 & 2 & 3 \end{array}]$

단계 1

Find the determinant.

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단계 1.1

Choose the row or column with the most

0

$0$ elements. If there are no

0

$0$ elements choose any row or column. Multiply every element in row

1

$1$ by its cofactor and add.

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단계 1.1.1

Consider the corresponding sign chart.

∣ ∣ ∣ ∣ \begin{matrix} + & - & + - & + & - + & - & + \end{matrix} ∣ ∣ ∣ ∣

$| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |$

단계 1.1.2

The cofactor is the minor with the sign changed if the indices match a

-

$-$ position on the sign chart.

단계 1.1.3

The minor for

a_{11}

$a_{11}$ is the determinant with row

1

$1$ and column

1

$1$ deleted.

∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} |$

단계 1.1.4

Multiply element

a_{11}

$a_{11}$ by its cofactor.

4 ∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣

$4 | \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} |$

단계 1.1.5

The minor for

a_{12}

$a_{12}$ is the determinant with row

1

$1$ and column

2

$2$ deleted.

∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} |$

단계 1.1.6

Multiply element

a_{12}

$a_{12}$ by its cofactor.

- 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣

$- 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} |$

단계 1.1.7

The minor for

a_{13}

$a_{13}$ is the determinant with row

1

$1$ and column

3

$3$ deleted.

∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$

단계 1.1.8

Multiply element

a_{13}

$a_{13}$ by its cofactor.

0 ∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$0 | \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$

단계 1.1.9

Add the terms together.

4 ∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣ - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0 ∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$4 | \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} | - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0 | \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$

4 ∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣ - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0 ∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$4 | \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} | - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0 | \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$

단계 1.2

0

$0$ 에

∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$ 을 곱합니다.

4 ∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣ - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 | \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} | - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

단계 1.3

∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} |$ 의 값을 구합니다.

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단계 1.3.1

2 \times 2

$2 \times 2$ 행렬의 행렬식은

∣ ∣ ∣ \begin{matrix} a & b c & d \end{matrix} ∣ ∣ ∣ = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ 공식을 이용해 계산합니다.

4 (3 \cdot 3 - 2 \cdot 1) - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 (3 \cdot 3 - 2 \cdot 1) - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

단계 1.3.2

행렬식을 간단히 합니다.

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단계 1.3.2.1

각 항을 간단히 합니다.

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단계 1.3.2.1.1

3

$3$ 에

3

$3$ 을 곱합니다.

4 (9 - 2 \cdot 1) - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 (9 - 2 \cdot 1) - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

단계 1.3.2.1.2

- 2

$- 2$ 에

1

$1$ 을 곱합니다.

4 (9 - 2) - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 (9 - 2) - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

4 (9 - 2) - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 (9 - 2) - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

단계 1.3.2.2

9

$9$ 에서

2

$2$ 을 뺍니다.

4 \cdot 7 - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 \cdot 7 - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

4 \cdot 7 - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 \cdot 7 - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

4 \cdot 7 - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 \cdot 7 - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

단계 1.4

∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} |$ 의 값을 구합니다.

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단계 1.4.1

2 \times 2

$2 \times 2$ 행렬의 행렬식은

∣ ∣ ∣ \begin{matrix} a & b c & d \end{matrix} ∣ ∣ ∣ = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ 공식을 이용해 계산합니다.

4 \cdot 7 - 4 (2 \cdot 3 - 1 \cdot 1) + 0

$4 \cdot 7 - 4 (2 \cdot 3 - 1 \cdot 1) + 0$

단계 1.4.2

행렬식을 간단히 합니다.

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단계 1.4.2.1

각 항을 간단히 합니다.

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단계 1.4.2.1.1

2

$2$ 에

3

$3$ 을 곱합니다.

4 \cdot 7 - 4 (6 - 1 \cdot 1) + 0

$4 \cdot 7 - 4 (6 - 1 \cdot 1) + 0$

단계 1.4.2.1.2

- 1

$- 1$ 에

1

$1$ 을 곱합니다.

4 \cdot 7 - 4 (6 - 1) + 0

$4 \cdot 7 - 4 (6 - 1) + 0$

4 \cdot 7 - 4 (6 - 1) + 0

$4 \cdot 7 - 4 (6 - 1) + 0$

단계 1.4.2.2

6

$6$ 에서

1

$1$ 을 뺍니다.

4 \cdot 7 - 4 \cdot 5 + 0

$4 \cdot 7 - 4 \cdot 5 + 0$

4 \cdot 7 - 4 \cdot 5 + 0

$4 \cdot 7 - 4 \cdot 5 + 0$

4 \cdot 7 - 4 \cdot 5 + 0

$4 \cdot 7 - 4 \cdot 5 + 0$

단계 1.5

행렬식을 간단히 합니다.

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단계 1.5.1

각 항을 간단히 합니다.

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단계 1.5.1.1

4

$4$ 에

7

$7$ 을 곱합니다.

28 - 4 \cdot 5 + 0

$28 - 4 \cdot 5 + 0$

단계 1.5.1.2

- 4

$- 4$ 에

5

$5$ 을 곱합니다.

28 - 20 + 0

$28 - 20 + 0$

28 - 20 + 0

$28 - 20 + 0$

단계 1.5.2

28

$28$ 에서

20

$20$ 을 뺍니다.

8 + 0

$8 + 0$

단계 1.5.3

8

$8$ 를

0

$0$ 에 더합니다.

8

$8$

8

$8$

8

$8$

단계 2

Since the determinant is non-zero, the inverse exists.

단계 3

Set up a

3 \times 6

$3 \times 6$ matrix where the left half is the original matrix and the right half is its identity matrix.

⎡ ⎢ ⎣ \begin{matrix} 4 & 4 & 0 & 1 & 0 & 0 2 & 3 & 1 & 0 & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} 4 & 4 & 0 & 1 & 0 & 0 \\ 2 & 3 & 1 & 0 & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

단계 4

기약 행 사다리꼴을 구합니다.

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단계 4.1

Multiply each element of

R_{1}

$R_{1}$ by

\frac{1}{4}

$\frac{1}{4}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

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단계 4.1.1

Multiply each element of

R_{1}

$R_{1}$ by

\frac{1}{4}

$\frac{1}{4}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

⎡ ⎢ ⎢ ⎣ \begin{matrix} \frac{4}{4} & \frac{4}{4} & \frac{0}{4} & \frac{1}{4} & \frac{0}{4} & \frac{0}{4} 2 & 3 & 1 & 0 & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} \frac{4}{4} & \frac{4}{4} & \frac{0}{4} & \frac{1}{4} & \frac{0}{4} & \frac{0}{4} \\ 2 & 3 & 1 & 0 & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

단계 4.1.2

R_{1}

$R_{1}$ 을 간단히 합니다.

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 2 & 3 & 1 & 0 & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 2 & 3 & 1 & 0 & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 2 & 3 & 1 & 0 & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 2 & 3 & 1 & 0 & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

단계 4.2

Perform the row operation

R_{2} = R_{2} - 2 R_{1}

$R_{2} = R_{2} - 2 R_{1}$ to make the entry at

2, 1

$2, 1$ a

0

$0$ .

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단계 4.2.1

Perform the row operation

R_{2} = R_{2} - 2 R_{1}

$R_{2} = R_{2} - 2 R_{1}$ to make the entry at

2, 1

$2, 1$ a

0

$0$ .

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 2 - 2 \cdot 1 & 3 - 2 \cdot 1 & 1 - 2 \cdot 0 & 0 - 2 (\frac{1}{4}) & 1 - 2 \cdot 0 & 0 - 2 \cdot 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 2 - 2 \cdot 1 & 3 - 2 \cdot 1 & 1 - 2 \cdot 0 & 0 - 2 (\frac{1}{4}) & 1 - 2 \cdot 0 & 0 - 2 \cdot 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

단계 4.2.2

R_{2}

$R_{2}$ 을 간단히 합니다.

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

단계 4.3

Perform the row operation

R_{3} = R_{3} - R_{1}

$R_{3} = R_{3} - R_{1}$ to make the entry at

3, 1

$3, 1$ a

0

$0$ .

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단계 4.3.1

Perform the row operation

R_{3} = R_{3} - R_{1}

$R_{3} = R_{3} - R_{1}$ to make the entry at

3, 1

$3, 1$ a

0

$0$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 1 - 1 & 2 - 1 & 3 - 0 & 0 - \frac{1}{4} & 0 - 0 & 1 - 0 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 1 - 1 & 2 - 1 & 3 - 0 & 0 - \frac{1}{4} & 0 - 0 & 1 - 0 \end{array}]$

단계 4.3.2

R_{3}

$R_{3}$ 을 간단히 합니다.

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 1 & 3 & - \frac{1}{4} & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 1 & 3 & - \frac{1}{4} & 0 & 1 \end{array}]$

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 1 & 3 & - \frac{1}{4} & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 1 & 3 & - \frac{1}{4} & 0 & 1 \end{array}]$

단계 4.4

Perform the row operation

R_{3} = R_{3} - R_{2}

$R_{3} = R_{3} - R_{2}$ to make the entry at

3, 2

$3, 2$ a

0

$0$ .

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단계 4.4.1

Perform the row operation

R_{3} = R_{3} - R_{2}

$R_{3} = R_{3} - R_{2}$ to make the entry at

3, 2

$3, 2$ a

0

$0$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 - 0 & 1 - 1 & 3 - 1 & - \frac{1}{4} + \frac{1}{2} & 0 - 1 & 1 - 0 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 - 0 & 1 - 1 & 3 - 1 & - \frac{1}{4} + \frac{1}{2} & 0 - 1 & 1 - 0 \end{array}]$

단계 4.4.2

R_{3}

$R_{3}$ 을 간단히 합니다.

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 0 & 2 & \frac{1}{4} & - 1 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 0 & 2 & \frac{1}{4} & - 1 & 1 \end{array}]$

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 0 & 2 & \frac{1}{4} & - 1 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 0 & 2 & \frac{1}{4} & - 1 & 1 \end{array}]$

단계 4.5

Multiply each element of

R_{3}

$R_{3}$ by

\frac{1}{2}

$\frac{1}{2}$ to make the entry at

3, 3

$3, 3$ a

1

$1$ .

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단계 4.5.1

Multiply each element of

R_{3}

$R_{3}$ by

\frac{1}{2}

$\frac{1}{2}$ to make the entry at

3, 3

$3, 3$ a

1

$1$ .

⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \frac{0}{2} & \frac{0}{2} & \frac{2}{2} & \frac{\frac{1}{4}}{2} & \frac{- 1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ \frac{0}{2} & \frac{0}{2} & \frac{2}{2} & \frac{\frac{1}{4}}{2} & \frac{- 1}{2} & \frac{1}{2} \end{array}]$

단계 4.5.2

R_{3}

$R_{3}$ 을 간단히 합니다.

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

단계 4.6

Perform the row operation

R_{2} = R_{2} - R_{3}

$R_{2} = R_{2} - R_{3}$ to make the entry at

2, 3

$2, 3$ a

0

$0$ .

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단계 4.6.1

Perform the row operation

R_{2} = R_{2} - R_{3}

$R_{2} = R_{2} - R_{3}$ to make the entry at

2, 3

$2, 3$ a

0

$0$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 - 0 & 1 - 0 & 1 - 1 & - \frac{1}{2} - \frac{1}{8} & 1 + \frac{1}{2} & 0 - \frac{1}{2} 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 - 0 & 1 - 0 & 1 - 1 & - \frac{1}{2} - \frac{1}{8} & 1 + \frac{1}{2} & 0 - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

단계 4.6.2

R_{2}

$R_{2}$ 을 간단히 합니다.

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

단계 4.7

Perform the row operation

R_{1} = R_{1} - R_{2}

$R_{1} = R_{1} - R_{2}$ to make the entry at

1, 2

$1, 2$ a

0

$0$ .

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 4.7.1

Perform the row operation

R_{1} = R_{1} - R_{2}

$R_{1} = R_{1} - R_{2}$ to make the entry at

1, 2

$1, 2$ a

0

$0$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 - 0 & 1 - 1 & 0 - 0 & \frac{1}{4} + \frac{5}{8} & 0 - \frac{3}{2} & 0 + \frac{1}{2} 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 - 0 & 1 - 1 & 0 - 0 & \frac{1}{4} + \frac{5}{8} & 0 - \frac{3}{2} & 0 + \frac{1}{2} \\ 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

단계 4.7.2

R_{1}

$R_{1}$ 을 간단히 합니다.

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 & \frac{7}{8} & - \frac{3}{2} & \frac{1}{2} 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 0 & 0 & \frac{7}{8} & - \frac{3}{2} & \frac{1}{2} \\ 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 & \frac{7}{8} & - \frac{3}{2} & \frac{1}{2} 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 & \frac{7}{8} & - \frac{3}{2} & \frac{1}{2} 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

단계 5

The right half of the reduced row echelon form is the inverse.

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} \frac{7}{8} & - \frac{3}{2} & \frac{1}{2} - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} \frac{7}{8} & - \frac{3}{2} & \frac{1}{2} \\ - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

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