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三角関数 例
sin(x)√1-sin2(x)sin(x)√1−sin2(x)
ステップ 1
ステップ 1.1
11を1212に書き換えます。
sin(x)√12-sin2(x)sin(x)√12−sin2(x)
ステップ 1.2
両項とも完全平方なので、平方の差の公式a2-b2=(a+b)(a-b)a2−b2=(a+b)(a−b)を利用して、因数分解します。このとき、a=1a=1であり、b=sin(x)b=sin(x)です。
sin(x)√(1+sin(x))(1-sin(x))sin(x)√(1+sin(x))(1−sin(x))
sin(x)√(1+sin(x))(1-sin(x))sin(x)√(1+sin(x))(1−sin(x))
ステップ 2
sin(x)√(1+sin(x))(1-sin(x))sin(x)√(1+sin(x))(1−sin(x))に√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))をかけます。
sin(x)√(1+sin(x))(1-sin(x))⋅√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))sin(x)√(1+sin(x))(1−sin(x))⋅√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))
ステップ 3
ステップ 3.1
sin(x)√(1+sin(x))(1-sin(x))sin(x)√(1+sin(x))(1−sin(x))に√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))をかけます。
sin(x)√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))sin(x)√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))
ステップ 3.2
√(1+sin(x))(1-sin(x))√(1+sin(x))(1−sin(x))を11乗します。
sin(x)√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))1√(1+sin(x))(1-sin(x))sin(x)√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))1√(1+sin(x))(1−sin(x))
ステップ 3.3
√(1+sin(x))(1-sin(x))√(1+sin(x))(1−sin(x))を11乗します。
sin(x)√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))1√(1+sin(x))(1-sin(x))1sin(x)√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))1√(1+sin(x))(1−sin(x))1
ステップ 3.4
べき乗則aman=am+naman=am+nを利用して指数を組み合わせます。
sin(x)√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))1+1sin(x)√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))1+1
ステップ 3.5
11と11をたし算します。
sin(x)√(1+sin(x))(1-sin(x))√(1+sin(x))(1-sin(x))2sin(x)√(1+sin(x))(1−sin(x))√(1+sin(x))(1−sin(x))2
ステップ 3.6
√(1+sin(x))(1-sin(x))2√(1+sin(x))(1−sin(x))2を(1+sin(x))(1-sin(x))(1+sin(x))(1−sin(x))に書き換えます。
ステップ 3.6.1
n√ax=axnn√ax=axnを利用し、√(1+sin(x))(1-sin(x))√(1+sin(x))(1−sin(x))を((1+sin(x))(1-sin(x)))12((1+sin(x))(1−sin(x)))12に書き換えます。
sin(x)√(1+sin(x))(1-sin(x))(((1+sin(x))(1-sin(x)))12)2sin(x)√(1+sin(x))(1−sin(x))(((1+sin(x))(1−sin(x)))12)2
ステップ 3.6.2
べき乗則を当てはめて、指数(am)n=amn(am)n=amnをかけ算します。
sin(x)√(1+sin(x))(1-sin(x))((1+sin(x))(1-sin(x)))12⋅2sin(x)√(1+sin(x))(1−sin(x))((1+sin(x))(1−sin(x)))12⋅2
ステップ 3.6.3
1212と22をまとめます。
sin(x)√(1+sin(x))(1-sin(x))((1+sin(x))(1-sin(x)))22sin(x)√(1+sin(x))(1−sin(x))((1+sin(x))(1−sin(x)))22
ステップ 3.6.4
22の共通因数を約分します。
ステップ 3.6.4.1
共通因数を約分します。
sin(x)√(1+sin(x))(1-sin(x))((1+sin(x))(1-sin(x)))22
ステップ 3.6.4.2
式を書き換えます。
sin(x)√(1+sin(x))(1-sin(x))((1+sin(x))(1-sin(x)))1
sin(x)√(1+sin(x))(1-sin(x))((1+sin(x))(1-sin(x)))1
ステップ 3.6.5
簡約します。
sin(x)√(1+sin(x))(1-sin(x))(1+sin(x))(1-sin(x))
sin(x)√(1+sin(x))(1-sin(x))(1+sin(x))(1-sin(x))
sin(x)√(1+sin(x))(1-sin(x))(1+sin(x))(1-sin(x))