線形代数例

⎡ ⎢ ⎣ \begin{matrix} 1 & 4 & 0 & 3 & 0 0 & 0 & 1 & - 3 & 0 0 & 0 & 0 & 0 & - 1 \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} 1 & 4 & 0 & 3 & 0 \\ 0 & 0 & 1 & - 3 & 0 \\ 0 & 0 & 0 & 0 & - 1 \end{array}]$

ステップ 1

Write as an augmented matrix for

$A x = 0$ .

$[\begin{array}{c} 1 & 4 & 0 & 3 & 0 & 0 \\ 0 & 0 & 1 & - 3 & 0 & 0 \\ 0 & 0 & 0 & 0 & - 1 & 0 \end{array}]$

ステップ 2

縮小行の階段形を求めます。

タップして手順をさらに表示してください…

ステップ 2.1

Multiply each element of

$R_{3}$ by

$- 1$ to make the entry at

$3, 5$ a

$1$ .

タップして手順をさらに表示してください…

ステップ 2.1.1

Multiply each element of

$R_{3}$ by

$- 1$ to make the entry at

$3, 5$ a

$1$ .

$[\begin{array}{c} 1 & 4 & 0 & 3 & 0 & 0 \\ 0 & 0 & 1 & - 3 & 0 & 0 \\ - 0 & - 0 & - 0 & - 0 & - - 1 & - 0 \end{array}]$

ステップ 2.1.2

$R_{3}$ を簡約します。

$[\begin{array}{c} 1 & 4 & 0 & 3 & 0 & 0 \\ 0 & 0 & 1 & - 3 & 0 & 0 \\ 0 & 0 & 0 & 0 & 1 & 0 \end{array}]$

ステップ 3

Use the result matrix to declare the final solution to the system of equations.

$x_{1} + 4 x_{2} + 3 x_{4} = 0$

$x_{3} - 3 x_{4} = 0$

$x_{5} = 0$

ステップ 4

Write a solution vector by solving in terms of the free variables in each row.

$[\begin{array}{c} x_{1} \\ x_{2} \\ x_{3} \\ x_{4} \\ x_{5} \end{array}] = [\begin{array}{c} - 4 x_{2} - 3 x_{4} \\ x_{2} \\ 3 x_{4} \\ x_{4} \\ 0 \end{array}]$

ステップ 5

Write the solution as a linear combination of vectors.

$[\begin{array}{c} x_{1} \\ x_{2} \\ x_{3} \\ x_{4} \\ x_{5} \end{array}] = x_{2} [\begin{array}{c} - 4 \\ 1 \\ 0 \\ 0 \\ 0 \end{array}] + x_{4} [\begin{array}{c} - 3 \\ 0 \\ 3 \\ 1 \\ 0 \end{array}]$

ステップ 6

Write as a solution set.

${x_{2} [\begin{array}{c} - 4 \\ 1 \\ 0 \\ 0 \\ 0 \end{array}] + x_{4} [\begin{array}{c} - 3 \\ 0 \\ 3 \\ 1 \\ 0 \end{array}] | x_{2}, x_{4} \in R}$

線形代数 例

線形代数例