化学例

$N i {(B r)}_{2}$

ステップ 1

$N i {(B r)}_{2}$ is soluble because most bromides are soluble except $A g B r$ , $H g B r_{2}$ , $H g_{2} B r_{2}$ , and $P b B r_{2}$ .

$N i {(B r)}_{2}$ は可溶性です

化学 例