基礎数学例

(- 4, - 8)

$(- 4, - 8)$

ステップ 1

The point is located in the third quadrant because

x

$x$ and

y

$y$ are both negative. The quadrants are labeled in counter-clockwise order, starting in the upper-right.

象限

3

$3$

ステップ 2

⎡ ⎢ ⎣ \begin{matrix} x^{2} & \frac{1}{2} \sqrt{π} & \int x d x \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

基礎数学 例