線形代数例

[\begin{matrix} 4 & 2 & 3 & 6 & - 7 1 & 0 & 1 & 0 & 1 \end{matrix}]

$[\begin{array}{c} 4 & 2 & 3 & 6 & - 7 \\ 1 & 0 & 1 & 0 & 1 \end{array}]$

ステップ 1

縮小行の階段形を求めます。

タップして手順をさらに表示してください…

ステップ 1.1

Multiply each element of

R_{1}

$R_{1}$ by

\frac{1}{4}

$\frac{1}{4}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

タップして手順をさらに表示してください…

ステップ 1.1.1

Multiply each element of

R_{1}

$R_{1}$ by

\frac{1}{4}

$\frac{1}{4}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

[\begin{matrix} \frac{4}{4} & \frac{2}{4} & \frac{3}{4} & \frac{6}{4} & \frac{- 7}{4} 1 & 0 & 1 & 0 & 1 \end{matrix}]

$[\begin{array}{c} \frac{4}{4} & \frac{2}{4} & \frac{3}{4} & \frac{6}{4} & \frac{- 7}{4} \\ 1 & 0 & 1 & 0 & 1 \end{array}]$

ステップ 1.1.2

R_{1}

$R_{1}$ を簡約します。

[\begin{matrix} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} 1 & 0 & 1 & 0 & 1 \end{matrix}]

$[\begin{array}{c} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} \\ 1 & 0 & 1 & 0 & 1 \end{array}]$

[\begin{matrix} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} 1 & 0 & 1 & 0 & 1 \end{matrix}]

$[\begin{array}{c} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} \\ 1 & 0 & 1 & 0 & 1 \end{array}]$

ステップ 1.2

Perform the row operation

R_{2} = R_{2} - R_{1}

$R_{2} = R_{2} - R_{1}$ to make the entry at

2, 1

$2, 1$ a

0

$0$ .

タップして手順をさらに表示してください…

ステップ 1.2.1

Perform the row operation

R_{2} = R_{2} - R_{1}

$R_{2} = R_{2} - R_{1}$ to make the entry at

2, 1

$2, 1$ a

0

$0$ .

[\begin{matrix} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} 1 - 1 & 0 - \frac{1}{2} & 1 - \frac{3}{4} & 0 - \frac{3}{2} & 1 + \frac{7}{4} \end{matrix}]

$[\begin{array}{c} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} \\ 1 - 1 & 0 - \frac{1}{2} & 1 - \frac{3}{4} & 0 - \frac{3}{2} & 1 + \frac{7}{4} \end{array}]$

ステップ 1.2.2

R_{2}

$R_{2}$ を簡約します。

[\begin{matrix} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} 0 & - \frac{1}{2} & \frac{1}{4} & - \frac{3}{2} & \frac{11}{4} \end{matrix}]

$[\begin{array}{c} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} \\ 0 & - \frac{1}{2} & \frac{1}{4} & - \frac{3}{2} & \frac{11}{4} \end{array}]$

[\begin{matrix} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} 0 & - \frac{1}{2} & \frac{1}{4} & - \frac{3}{2} & \frac{11}{4} \end{matrix}]

$[\begin{array}{c} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} \\ 0 & - \frac{1}{2} & \frac{1}{4} & - \frac{3}{2} & \frac{11}{4} \end{array}]$

ステップ 1.3

Multiply each element of

R_{2}

$R_{2}$ by

- 2

$- 2$ to make the entry at

2, 2

$2, 2$ a

1

$1$ .

タップして手順をさらに表示してください…

ステップ 1.3.1

Multiply each element of

R_{2}

$R_{2}$ by

- 2

$- 2$ to make the entry at

2, 2

$2, 2$ a

1

$1$ .

⎡ ⎢ ⎣ \begin{matrix} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} - 2 \cdot 0 & - 2 (- \frac{1}{2}) & - 2 (\frac{1}{4}) & - 2 (- \frac{3}{2}) & - 2 (\frac{11}{4}) \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} \\ - 2 \cdot 0 & - 2 (- \frac{1}{2}) & - 2 (\frac{1}{4}) & - 2 (- \frac{3}{2}) & - 2 (\frac{11}{4}) \end{array}]$

ステップ 1.3.2

R_{2}

$R_{2}$ を簡約します。

[\begin{matrix} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{matrix}]

$[\begin{array}{c} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} \\ 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{array}]$

[\begin{matrix} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{matrix}]

$[\begin{array}{c} 1 & \frac{1}{2} & \frac{3}{4} & \frac{3}{2} & - \frac{7}{4} \\ 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{array}]$

ステップ 1.4

Perform the row operation

R_{1} = R_{1} - \frac{1}{2} R_{2}

$R_{1} = R_{1} - \frac{1}{2} R_{2}$ to make the entry at

1, 2

$1, 2$ a

0

$0$ .

タップして手順をさらに表示してください…

ステップ 1.4.1

Perform the row operation

R_{1} = R_{1} - \frac{1}{2} R_{2}

$R_{1} = R_{1} - \frac{1}{2} R_{2}$ to make the entry at

1, 2

$1, 2$ a

0

$0$ .

[\begin{matrix} 1 - \frac{1}{2} \cdot 0 & \frac{1}{2} - \frac{1}{2} \cdot 1 & \frac{3}{4} - \frac{1}{2} (- \frac{1}{2}) & \frac{3}{2} - \frac{1}{2} \cdot 3 & - \frac{7}{4} - \frac{1}{2} (- \frac{11}{2}) 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{matrix}]

$[\begin{array}{c} 1 - \frac{1}{2} \cdot 0 & \frac{1}{2} - \frac{1}{2} \cdot 1 & \frac{3}{4} - \frac{1}{2} (- \frac{1}{2}) & \frac{3}{2} - \frac{1}{2} \cdot 3 & - \frac{7}{4} - \frac{1}{2} (- \frac{11}{2}) \\ 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{array}]$

ステップ 1.4.2

R_{1}

$R_{1}$ を簡約します。

[\begin{matrix} 1 & 0 & 1 & 0 & 1 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{matrix}]

$[\begin{array}{c} 1 & 0 & 1 & 0 & 1 \\ 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{array}]$

[\begin{matrix} 1 & 0 & 1 & 0 & 1 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{matrix}]

$[\begin{array}{c} 1 & 0 & 1 & 0 & 1 \\ 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{array}]$

[\begin{matrix} 1 & 0 & 1 & 0 & 1 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{matrix}]

$[\begin{array}{c} 1 & 0 & 1 & 0 & 1 \\ 0 & 1 & - \frac{1}{2} & 3 & - \frac{11}{2} \end{array}]$

ステップ 2

The pivot positions are the locations with the leading

1

$1$ in each row. The pivot columns are the columns that have a pivot position.

Pivot Positions:

a_{11}

$a_{11}$ and

a_{22}

$a_{22}$

Pivot Columns:

1

$1$ and

2

$2$

ステップ 3

The rank is the number of pivot columns.

2

$2$

問題を入力

線形代数 例

線形代数例