Matematica discreta Esempi

$x + y + z = 1$ , $x + 3 y + 3 z = - 3$ , $x - y + z = 3$

Passaggio 1

Write the system as a matrix.

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 1 & 3 & 3 & - 3 \\ 1 & - 1 & 1 & 3 \end{array}]$

Passaggio 2

Trova la forma ridotta a scala per righe di Echelon.

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Passaggio 2.1

Perform the row operation $R_{2} = R_{2} - R_{1}$ to make the entry at $2, 1$ a $0$ .

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Passaggio 2.1.1

Perform the row operation $R_{2} = R_{2} - R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 1 - 1 & 3 - 1 & 3 - 1 & - 3 - 1 \\ 1 & - 1 & 1 & 3 \end{array}]$

Passaggio 2.1.2

Semplifica $R_{2}$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 2 & 2 & - 4 \\ 1 & - 1 & 1 & 3 \end{array}]$

Passaggio 2.2

Perform the row operation $R_{3} = R_{3} - R_{1}$ to make the entry at $3, 1$ a $0$ .

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Passaggio 2.2.1

Perform the row operation $R_{3} = R_{3} - R_{1}$ to make the entry at $3, 1$ a $0$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 2 & 2 & - 4 \\ 1 - 1 & - 1 - 1 & 1 - 1 & 3 - 1 \end{array}]$

Passaggio 2.2.2

Semplifica $R_{3}$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 2 & 2 & - 4 \\ 0 & - 2 & 0 & 2 \end{array}]$

Passaggio 2.3

Multiply each element of $R_{2}$ by $\frac{1}{2}$ to make the entry at $2, 2$ a $1$ .

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Passaggio 2.3.1

Multiply each element of $R_{2}$ by $\frac{1}{2}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ \frac{0}{2} & \frac{2}{2} & \frac{2}{2} & \frac{- 4}{2} \\ 0 & - 2 & 0 & 2 \end{array}]$

Passaggio 2.3.2

Semplifica $R_{2}$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 1 & 1 & - 2 \\ 0 & - 2 & 0 & 2 \end{array}]$

Passaggio 2.4

Perform the row operation $R_{3} = R_{3} + 2 R_{2}$ to make the entry at $3, 2$ a $0$ .

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Passaggio 2.4.1

Perform the row operation $R_{3} = R_{3} + 2 R_{2}$ to make the entry at $3, 2$ a $0$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 1 & 1 & - 2 \\ 0 + 2 \cdot 0 & - 2 + 2 \cdot 1 & 0 + 2 \cdot 1 & 2 + 2 \cdot - 2 \end{array}]$

Passaggio 2.4.2

Semplifica $R_{3}$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 1 & 1 & - 2 \\ 0 & 0 & 2 & - 2 \end{array}]$

Passaggio 2.5

Multiply each element of $R_{3}$ by $\frac{1}{2}$ to make the entry at $3, 3$ a $1$ .

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Passaggio 2.5.1

Multiply each element of $R_{3}$ by $\frac{1}{2}$ to make the entry at $3, 3$ a $1$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 1 & 1 & - 2 \\ \frac{0}{2} & \frac{0}{2} & \frac{2}{2} & \frac{- 2}{2} \end{array}]$

Passaggio 2.5.2

Semplifica $R_{3}$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 1 & 1 & - 2 \\ 0 & 0 & 1 & - 1 \end{array}]$

Passaggio 2.6

Perform the row operation $R_{2} = R_{2} - R_{3}$ to make the entry at $2, 3$ a $0$ .

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Passaggio 2.6.1

Perform the row operation $R_{2} = R_{2} - R_{3}$ to make the entry at $2, 3$ a $0$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 - 0 & 1 - 0 & 1 - 1 & - 2 + 1 \\ 0 & 0 & 1 & - 1 \end{array}]$

Passaggio 2.6.2

Semplifica $R_{2}$ .

$[\begin{array}{c} 1 & 1 & 1 & 1 \\ 0 & 1 & 0 & - 1 \\ 0 & 0 & 1 & - 1 \end{array}]$

Passaggio 2.7

Perform the row operation $R_{1} = R_{1} - R_{3}$ to make the entry at $1, 3$ a $0$ .

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Passaggio 2.7.1

Perform the row operation $R_{1} = R_{1} - R_{3}$ to make the entry at $1, 3$ a $0$ .

$[\begin{array}{c} 1 - 0 & 1 - 0 & 1 - 1 & 1 + 1 \\ 0 & 1 & 0 & - 1 \\ 0 & 0 & 1 & - 1 \end{array}]$

Passaggio 2.7.2

Semplifica $R_{1}$ .

$[\begin{array}{c} 1 & 1 & 0 & 2 \\ 0 & 1 & 0 & - 1 \\ 0 & 0 & 1 & - 1 \end{array}]$

Passaggio 2.8

Perform the row operation $R_{1} = R_{1} - R_{2}$ to make the entry at $1, 2$ a $0$ .

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Passaggio 2.8.1

Perform the row operation $R_{1} = R_{1} - R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - 0 & 1 - 1 & 0 - 0 & 2 + 1 \\ 0 & 1 & 0 & - 1 \\ 0 & 0 & 1 & - 1 \end{array}]$

Passaggio 2.8.2

Semplifica $R_{1}$ .

$[\begin{array}{c} 1 & 0 & 0 & 3 \\ 0 & 1 & 0 & - 1 \\ 0 & 0 & 1 & - 1 \end{array}]$

Passaggio 3

Use the result matrix to declare the final solution to the system of equations.

$x = 3$

$y = - 1$

$z = - 1$

Passaggio 4

The solution is the set of ordered pairs that make the system true.

$(3, - 1, - 1)$