Matematica discreta Esempi

$x + 2 y = - 6$ , $- 5 x + 3 y = 4$

Passaggio 1

Write the system as a matrix.

$[\begin{array}{c} 1 & 2 & - 6 \\ - 5 & 3 & 4 \end{array}]$

Passaggio 2

Trova la forma ridotta a scala per righe di Echelon.

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Passaggio 2.1

Perform the row operation $R_{2} = R_{2} + 5 R_{1}$ to make the entry at $2, 1$ a $0$ .

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Passaggio 2.1.1

Perform the row operation $R_{2} = R_{2} + 5 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & 2 & - 6 \\ - 5 + 5 \cdot 1 & 3 + 5 \cdot 2 & 4 + 5 \cdot - 6 \end{array}]$

Passaggio 2.1.2

Semplifica $R_{2}$ .

$[\begin{array}{c} 1 & 2 & - 6 \\ 0 & 13 & - 26 \end{array}]$

Passaggio 2.2

Multiply each element of $R_{2}$ by $\frac{1}{13}$ to make the entry at $2, 2$ a $1$ .

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Passaggio 2.2.1

Multiply each element of $R_{2}$ by $\frac{1}{13}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & 2 & - 6 \\ \frac{0}{13} & \frac{13}{13} & \frac{- 26}{13} \end{array}]$

Passaggio 2.2.2

Semplifica $R_{2}$ .

$[\begin{array}{c} 1 & 2 & - 6 \\ 0 & 1 & - 2 \end{array}]$

Passaggio 2.3

Perform the row operation $R_{1} = R_{1} - 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

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Passaggio 2.3.1

Perform the row operation $R_{1} = R_{1} - 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - 2 \cdot 0 & 2 - 2 \cdot 1 & - 6 - 2 \cdot - 2 \\ 0 & 1 & - 2 \end{array}]$

Passaggio 2.3.2

Semplifica $R_{1}$ .

$[\begin{array}{c} 1 & 0 & - 2 \\ 0 & 1 & - 2 \end{array}]$

Passaggio 3

Use the result matrix to declare the final solution to the system of equations.

$x = - 2$

$y = - 2$

Passaggio 4

The solution is the set of ordered pairs that make the system true.

$(- 2, - 2)$