Matematica discreta Esempi

Risolvi usando una matrice per eliminazione
2x-y+3z=82xy+3z=8 , x-6y-z=0x6yz=0 , -6x+3y-9z=246x+3y9z=24
Passaggio 1
Write the system as a matrix.
[2-1381-6-10-63-924]⎢ ⎢2138161063924⎥ ⎥
Passaggio 2
Trova la forma ridotta a scala per righe di Echelon.
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Passaggio 2.1
Multiply each element of R1R1 by 1212 to make the entry at 1,11,1 a 11.
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Passaggio 2.1.1
Multiply each element of R1R1 by 1212 to make the entry at 1,11,1 a 11.
[22-1232821-6-10-63-924]⎢ ⎢ ⎢22123282161063924⎥ ⎥ ⎥
Passaggio 2.1.2
Semplifica R1R1.
[1-123241-6-10-63-924]⎢ ⎢112324161063924⎥ ⎥
[1-123241-6-10-63-924]⎢ ⎢112324161063924⎥ ⎥
Passaggio 2.2
Perform the row operation R2=R2-R1R2=R2R1 to make the entry at 2,12,1 a 00.
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Passaggio 2.2.1
Perform the row operation R2=R2-R1R2=R2R1 to make the entry at 2,12,1 a 00.
[1-123241-1-6+12-1-320-4-63-924]⎢ ⎢ ⎢112324116+121320463924⎥ ⎥ ⎥
Passaggio 2.2.2
Semplifica R2R2.
[1-123240-112-52-4-63-924]⎢ ⎢ ⎢112324011252463924⎥ ⎥ ⎥
[1-123240-112-52-4-63-924]⎢ ⎢ ⎢112324011252463924⎥ ⎥ ⎥
Passaggio 2.3
Perform the row operation R3=R3+6R1R3=R3+6R1 to make the entry at 3,13,1 a 00.
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Passaggio 2.3.1
Perform the row operation R3=R3+6R1R3=R3+6R1 to make the entry at 3,13,1 a 00.
[1-123240-112-52-4-6+613+6(-12)-9+6(32)24+64]⎢ ⎢ ⎢ ⎢ ⎢11232401125246+613+6(12)9+6(32)24+64⎥ ⎥ ⎥ ⎥ ⎥
Passaggio 2.3.2
Semplifica R3R3.
[1-123240-112-52-400048]⎢ ⎢ ⎢112324011252400048⎥ ⎥ ⎥
[1-123240-112-52-400048]⎢ ⎢ ⎢112324011252400048⎥ ⎥ ⎥
Passaggio 2.4
Multiply each element of R2R2 by -211211 to make the entry at 2,22,2 a 11.
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Passaggio 2.4.1
Multiply each element of R2R2 by -211211 to make the entry at 2,22,2 a 11.
[1-12324-2110-211(-112)-211(-52)-211-400048]⎢ ⎢ ⎢ ⎢1123242110211(112)211(52)211400048⎥ ⎥ ⎥ ⎥
Passaggio 2.4.2
Semplifica R2R2.
[1-123240151181100048]⎢ ⎢ ⎢1123240151181100048⎥ ⎥ ⎥
[1-123240151181100048]⎢ ⎢ ⎢1123240151181100048⎥ ⎥ ⎥
Passaggio 2.5
Multiply each element of R3R3 by 148148 to make the entry at 3,43,4 a 11.
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Passaggio 2.5.1
Multiply each element of R3R3 by 148148 to make the entry at 3,43,4 a 11.
[1-12324015118110480480484848]⎢ ⎢ ⎢ ⎢112324015118110480480484848⎥ ⎥ ⎥ ⎥
Passaggio 2.5.2
Semplifica R3R3.
[1-12324015118110001]⎢ ⎢ ⎢112324015118110001⎥ ⎥ ⎥
[1-12324015118110001]⎢ ⎢ ⎢112324015118110001⎥ ⎥ ⎥
Passaggio 2.6
Perform the row operation R2=R2-811R3R2=R2811R3 to make the entry at 2,42,4 a 00.
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Passaggio 2.6.1
Perform the row operation R2=R2-811R3R2=R2811R3 to make the entry at 2,42,4 a 00.
[1-123240-81101-8110511-8110811-81110001]⎢ ⎢ ⎢1123240811018110511811081181110001⎥ ⎥ ⎥
Passaggio 2.6.2
Semplifica R2R2.
[1-123240151100001]⎢ ⎢ ⎢1123240151100001⎥ ⎥ ⎥
[1-123240151100001]⎢ ⎢ ⎢1123240151100001⎥ ⎥ ⎥
Passaggio 2.7
Perform the row operation R1=R1-4R3R1=R14R3 to make the entry at 1,41,4 a 00.
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Passaggio 2.7.1
Perform the row operation R1=R1-4R3R1=R14R3 to make the entry at 1,41,4 a 00.
[1-40-12-4032-404-410151100001]⎢ ⎢ ⎢140124032404410151100001⎥ ⎥ ⎥
Passaggio 2.7.2
Semplifica R1R1.
[1-123200151100001]⎢ ⎢ ⎢1123200151100001⎥ ⎥ ⎥
[1-123200151100001]⎢ ⎢ ⎢1123200151100001⎥ ⎥ ⎥
Passaggio 2.8
Perform the row operation R1=R1+12R2R1=R1+12R2 to make the entry at 1,21,2 a 00.
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Passaggio 2.8.1
Perform the row operation R1=R1+12R2R1=R1+12R2 to make the entry at 1,21,2 a 00.
[1+120-12+12132+125110+1200151100001]⎢ ⎢ ⎢1+12012+12132+125110+1200151100001⎥ ⎥ ⎥
Passaggio 2.8.2
Semplifica R1R1.
[10191100151100001]⎢ ⎢ ⎢10191100151100001⎥ ⎥ ⎥
[10191100151100001]⎢ ⎢ ⎢10191100151100001⎥ ⎥ ⎥
[10191100151100001]⎢ ⎢ ⎢10191100151100001⎥ ⎥ ⎥
Passaggio 3
Use the result matrix to declare the final solution to the system of equations.
x+1911z=0
y+511z=0
0=1
Passaggio 4
The system is inconsistent so there is no solution.
Nessuna soluzione
Inserisci il TUO problema
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