Matematica discreta Esempi

[330103020]330103020
Passaggio 1
Find the determinant.
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Passaggio 1.1
Choose the row or column with the most 00 elements. If there are no 00 elements choose any row or column. Multiply every element in row 33 by its cofactor and add.
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Passaggio 1.1.1
Consider the corresponding sign chart.
|+-+-+-+-+|∣ ∣+++++∣ ∣
Passaggio 1.1.2
The cofactor is the minor with the sign changed if the indices match a - position on the sign chart.
Passaggio 1.1.3
The minor for a31a31 is the determinant with row 33 and column 11 deleted.
|3003|3003
Passaggio 1.1.4
Multiply element a31a31 by its cofactor.
0|3003|03003
Passaggio 1.1.5
The minor for a32a32 is the determinant with row 33 and column 22 deleted.
|3013|3013
Passaggio 1.1.6
Multiply element a32a32 by its cofactor.
-2|3013|23013
Passaggio 1.1.7
The minor for a33a33 is the determinant with row 33 and column 33 deleted.
|3310|3310
Passaggio 1.1.8
Multiply element a33a33 by its cofactor.
0|3310|03310
Passaggio 1.1.9
Add the terms together.
0|3003|-2|3013|+0|3310|0300323013+03310
0|3003|-2|3013|+0|3310|0300323013+03310
Passaggio 1.2
Moltiplica 00 per |3003|3003.
0-2|3013|+0|3310|023013+03310
Passaggio 1.3
Moltiplica 00 per |3310|3310.
0-2|3013|+0023013+0
Passaggio 1.4
Calcola |3013|3013.
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Passaggio 1.4.1
È possibile trovare il determinante di una matrice 2×22×2 usando la formula |abcd|=ad-cbabcd=adcb.
0-2(33-10)+002(3310)+0
Passaggio 1.4.2
Semplifica il determinante.
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Passaggio 1.4.2.1
Moltiplica 33 per 33.
0-2(9-10)+002(910)+0
Passaggio 1.4.2.2
Sottrai 00 da 99.
0-29+0029+0
0-29+0029+0
0-29+0029+0
Passaggio 1.5
Semplifica il determinante.
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Passaggio 1.5.1
Moltiplica -22 per 99.
0-18+0018+0
Passaggio 1.5.2
Sottrai 1818 da 00.
-18+018+0
Passaggio 1.5.3
Somma -1818 e 00.
-1818
-1818
-1818
Passaggio 2
Since the determinant is non-zero, the inverse exists.
Passaggio 3
Set up a 3×63×6 matrix where the left half is the original matrix and the right half is its identity matrix.
[330100103010020001]330100103010020001
Passaggio 4
Trova la forma ridotta a scala per righe di Echelon.
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Passaggio 4.1
Multiply each element of R1R1 by 1313 to make the entry at 1,11,1 a 11.
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Passaggio 4.1.1
Multiply each element of R1R1 by 1313 to make the entry at 1,11,1 a 11.
[333303130303103010020001]⎢ ⎢333303130303103010020001⎥ ⎥
Passaggio 4.1.2
Semplifica R1R1.
[1101300103010020001]⎢ ⎢1101300103010020001⎥ ⎥
[1101300103010020001]⎢ ⎢1101300103010020001⎥ ⎥
Passaggio 4.2
Perform the row operation R2=R2-R1R2=R2R1 to make the entry at 2,12,1 a 00.
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Passaggio 4.2.1
Perform the row operation R2=R2-R1R2=R2R1 to make the entry at 2,12,1 a 00.
[11013001-10-13-00-131-00-0020001]⎢ ⎢11013001101300131000020001⎥ ⎥
Passaggio 4.2.2
Semplifica R2R2.
[11013000-13-1310020001]⎢ ⎢11013000131310020001⎥ ⎥
[11013000-13-1310020001]⎢ ⎢11013000131310020001⎥ ⎥
Passaggio 4.3
Multiply each element of R2R2 by -11 to make the entry at 2,22,2 a 11.
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Passaggio 4.3.1
Multiply each element of R2R2 by -11 to make the entry at 2,22,2 a 11.
[1101300-0--1-13--13-11-0020001]⎢ ⎢1101300011313110020001⎥ ⎥
Passaggio 4.3.2
Semplifica R2R2.
[110130001-313-10020001]⎢ ⎢11013000131310020001⎥ ⎥
[110130001-313-10020001]⎢ ⎢11013000131310020001⎥ ⎥
Passaggio 4.4
Perform the row operation R3=R3-2R2R3=R32R2 to make the entry at 3,23,2 a 00.
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Passaggio 4.4.1
Perform the row operation R3=R3-2R2R3=R32R2 to make the entry at 3,23,2 a 00.
[110130001-313-100-202-210-2-30-2(13)0-2-11-20]⎢ ⎢ ⎢ ⎢1101300013131002022102302(13)021120⎥ ⎥ ⎥ ⎥
Passaggio 4.4.2
Semplifica R3R3.
[110130001-313-10006-2321]⎢ ⎢ ⎢110130001313100062321⎥ ⎥ ⎥
[110130001-313-10006-2321]⎢ ⎢ ⎢110130001313100062321⎥ ⎥ ⎥
Passaggio 4.5
Multiply each element of R3R3 by 1616 to make the entry at 3,33,3 a 11.
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Passaggio 4.5.1
Multiply each element of R3R3 by 1616 to make the entry at 3,33,3 a 11.
[110130001-313-10060666-2362616]⎢ ⎢ ⎢ ⎢110130001313100606662362616⎥ ⎥ ⎥ ⎥
Passaggio 4.5.2
Semplifica R3R3.
[110130001-313-10001-191316]⎢ ⎢ ⎢11013000131310001191316⎥ ⎥ ⎥
[110130001-313-10001-191316]⎢ ⎢ ⎢11013000131310001191316⎥ ⎥ ⎥
Passaggio 4.6
Perform the row operation R2=R2+3R3R2=R2+3R3 to make the entry at 2,32,3 a 00.
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Passaggio 4.6.1
Perform the row operation R2=R2+3R3R2=R2+3R3 to make the entry at 2,32,3 a 00.
[11013000+301+30-3+3113+3(-19)-1+3(13)0+3(16)001-191316]⎢ ⎢ ⎢ ⎢11013000+301+303+3113+3(19)1+3(13)0+3(16)001191316⎥ ⎥ ⎥ ⎥
Passaggio 4.6.2
Semplifica R2R2.
[11013000100012001-191316]⎢ ⎢ ⎢11013000100012001191316⎥ ⎥ ⎥
[11013000100012001-191316]⎢ ⎢ ⎢11013000100012001191316⎥ ⎥ ⎥
Passaggio 4.7
Perform the row operation R1=R1-R2R1=R1R2 to make the entry at 1,21,2 a 00.
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Passaggio 4.7.1
Perform the row operation R1=R1-R2R1=R1R2 to make the entry at 1,21,2 a 00.
[1-01-10-013-00-00-120100012001-191316]⎢ ⎢ ⎢101100130000120100012001191316⎥ ⎥ ⎥
Passaggio 4.7.2
Semplifica R1R1.
[100130-120100012001-191316]
[100130-120100012001-191316]
[100130-120100012001-191316]
Passaggio 5
The right half of the reduced row echelon form is the inverse.
[130-120012-191316]
Inserisci il TUO problema
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