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⎡ ⎢ ⎣ \begin{matrix} 4 & 4 & 0 2 & 3 & 1 1 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} 4 & 4 & 0 \\ 2 & 3 & 1 \\ 1 & 2 & 3 \end{array}]$

Langkah 1

Find the determinant.

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Langkah 1.1

Choose the row or column with the most

0

$0$ elements. If there are no

0

$0$ elements choose any row or column. Multiply every element in row

1

$1$ by its cofactor and add.

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Langkah 1.1.1

Consider the corresponding sign chart.

∣ ∣ ∣ ∣ \begin{matrix} + & - & + - & + & - + & - & + \end{matrix} ∣ ∣ ∣ ∣

$| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |$

Langkah 1.1.2

The cofactor is the minor with the sign changed if the indices match a

-

$-$ position on the sign chart.

Langkah 1.1.3

The minor for

a_{11}

$a_{11}$ is the determinant with row

1

$1$ and column

1

$1$ deleted.

∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} |$

Langkah 1.1.4

Multiply element

a_{11}

$a_{11}$ by its cofactor.

4 ∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣

$4 | \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} |$

Langkah 1.1.5

The minor for

a_{12}

$a_{12}$ is the determinant with row

1

$1$ and column

2

$2$ deleted.

∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} |$

Langkah 1.1.6

Multiply element

a_{12}

$a_{12}$ by its cofactor.

- 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣

$- 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} |$

Langkah 1.1.7

The minor for

a_{13}

$a_{13}$ is the determinant with row

1

$1$ and column

3

$3$ deleted.

∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$

Langkah 1.1.8

Multiply element

a_{13}

$a_{13}$ by its cofactor.

0 ∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$0 | \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$

Langkah 1.1.9

Add the terms together.

4 ∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣ - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0 ∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$4 | \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} | - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0 | \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$

4 ∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣ - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0 ∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$4 | \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} | - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0 | \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$

Langkah 1.2

Kalikan

0

$0$ dengan

∣ ∣ ∣ \begin{matrix} 2 & 3 1 & 2 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 2 & 3 \\ 1 & 2 \end{array} |$ .

4 ∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣ - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 | \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} | - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

Langkah 1.3

Evaluasi

∣ ∣ ∣ \begin{matrix} 3 & 1 2 & 3 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 3 & 1 \\ 2 & 3 \end{array} |$ .

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Langkah 1.3.1

Determinan dari matriks

2 \times 2

$2 \times 2$ dapat dicari menggunakan rumus

∣ ∣ ∣ \begin{matrix} a & b c & d \end{matrix} ∣ ∣ ∣ = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

4 (3 \cdot 3 - 2 \cdot 1) - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 (3 \cdot 3 - 2 \cdot 1) - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

Langkah 1.3.2

Sederhanakan determinannya.

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Langkah 1.3.2.1

Sederhanakan setiap suku.

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Langkah 1.3.2.1.1

Kalikan

3

$3$ dengan

3

$3$ .

4 (9 - 2 \cdot 1) - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 (9 - 2 \cdot 1) - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

Langkah 1.3.2.1.2

Kalikan

- 2

$- 2$ dengan

1

$1$ .

4 (9 - 2) - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 (9 - 2) - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

4 (9 - 2) - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 (9 - 2) - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

Langkah 1.3.2.2

Kurangi

2

$2$ dengan

9

$9$ .

4 \cdot 7 - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 \cdot 7 - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

4 \cdot 7 - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 \cdot 7 - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

4 \cdot 7 - 4 ∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣ + 0

$4 \cdot 7 - 4 | \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} | + 0$

Langkah 1.4

Evaluasi

∣ ∣ ∣ \begin{matrix} 2 & 1 1 & 3 \end{matrix} ∣ ∣ ∣

$| \begin{array}{c} 2 & 1 \\ 1 & 3 \end{array} |$ .

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Langkah 1.4.1

Determinan dari matriks

2 \times 2

$2 \times 2$ dapat dicari menggunakan rumus

∣ ∣ ∣ \begin{matrix} a & b c & d \end{matrix} ∣ ∣ ∣ = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

4 \cdot 7 - 4 (2 \cdot 3 - 1 \cdot 1) + 0

$4 \cdot 7 - 4 (2 \cdot 3 - 1 \cdot 1) + 0$

Langkah 1.4.2

Sederhanakan determinannya.

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Langkah 1.4.2.1

Sederhanakan setiap suku.

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Langkah 1.4.2.1.1

Kalikan

2

$2$ dengan

3

$3$ .

4 \cdot 7 - 4 (6 - 1 \cdot 1) + 0

$4 \cdot 7 - 4 (6 - 1 \cdot 1) + 0$

Langkah 1.4.2.1.2

Kalikan

- 1

$- 1$ dengan

1

$1$ .

4 \cdot 7 - 4 (6 - 1) + 0

$4 \cdot 7 - 4 (6 - 1) + 0$

4 \cdot 7 - 4 (6 - 1) + 0

$4 \cdot 7 - 4 (6 - 1) + 0$

Langkah 1.4.2.2

Kurangi

1

$1$ dengan

6

$6$ .

4 \cdot 7 - 4 \cdot 5 + 0

$4 \cdot 7 - 4 \cdot 5 + 0$

4 \cdot 7 - 4 \cdot 5 + 0

$4 \cdot 7 - 4 \cdot 5 + 0$

4 \cdot 7 - 4 \cdot 5 + 0

$4 \cdot 7 - 4 \cdot 5 + 0$

Langkah 1.5

Sederhanakan determinannya.

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Langkah 1.5.1

Sederhanakan setiap suku.

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Langkah 1.5.1.1

Kalikan

4

$4$ dengan

7

$7$ .

28 - 4 \cdot 5 + 0

$28 - 4 \cdot 5 + 0$

Langkah 1.5.1.2

Kalikan

- 4

$- 4$ dengan

5

$5$ .

28 - 20 + 0

$28 - 20 + 0$

28 - 20 + 0

$28 - 20 + 0$

Langkah 1.5.2

Kurangi

20

$20$ dengan

28

$28$ .

8 + 0

$8 + 0$

Langkah 1.5.3

Tambahkan

8

$8$ dan

0

$0$ .

8

$8$

8

$8$

8

$8$

Langkah 2

Since the determinant is non-zero, the inverse exists.

Langkah 3

Set up a

3 \times 6

$3 \times 6$ matrix where the left half is the original matrix and the right half is its identity matrix.

⎡ ⎢ ⎣ \begin{matrix} 4 & 4 & 0 & 1 & 0 & 0 2 & 3 & 1 & 0 & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} 4 & 4 & 0 & 1 & 0 & 0 \\ 2 & 3 & 1 & 0 & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

Langkah 4

Tentukan bentuk eselon baris yang dikurangi.

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Langkah 4.1

Multiply each element of

R_{1}

$R_{1}$ by

\frac{1}{4}

$\frac{1}{4}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

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Langkah 4.1.1

Multiply each element of

R_{1}

$R_{1}$ by

\frac{1}{4}

$\frac{1}{4}$ to make the entry at

1, 1

$1, 1$ a

1

$1$ .

⎡ ⎢ ⎢ ⎣ \begin{matrix} \frac{4}{4} & \frac{4}{4} & \frac{0}{4} & \frac{1}{4} & \frac{0}{4} & \frac{0}{4} 2 & 3 & 1 & 0 & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} \frac{4}{4} & \frac{4}{4} & \frac{0}{4} & \frac{1}{4} & \frac{0}{4} & \frac{0}{4} \\ 2 & 3 & 1 & 0 & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

Langkah 4.1.2

Sederhanakan

R_{1}

$R_{1}$ .

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 2 & 3 & 1 & 0 & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 2 & 3 & 1 & 0 & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 2 & 3 & 1 & 0 & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 2 & 3 & 1 & 0 & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

Langkah 4.2

Perform the row operation

R_{2} = R_{2} - 2 R_{1}

$R_{2} = R_{2} - 2 R_{1}$ to make the entry at

2, 1

$2, 1$ a

0

$0$ .

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Langkah 4.2.1

Perform the row operation

R_{2} = R_{2} - 2 R_{1}

$R_{2} = R_{2} - 2 R_{1}$ to make the entry at

2, 1

$2, 1$ a

0

$0$ .

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 2 - 2 \cdot 1 & 3 - 2 \cdot 1 & 1 - 2 \cdot 0 & 0 - 2 (\frac{1}{4}) & 1 - 2 \cdot 0 & 0 - 2 \cdot 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 2 - 2 \cdot 1 & 3 - 2 \cdot 1 & 1 - 2 \cdot 0 & 0 - 2 (\frac{1}{4}) & 1 - 2 \cdot 0 & 0 - 2 \cdot 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

Langkah 4.2.2

Sederhanakan

R_{2}

$R_{2}$ .

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 1 & 2 & 3 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 1 & 2 & 3 & 0 & 0 & 1 \end{array}]$

Langkah 4.3

Perform the row operation

R_{3} = R_{3} - R_{1}

$R_{3} = R_{3} - R_{1}$ to make the entry at

3, 1

$3, 1$ a

0

$0$ .

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Langkah 4.3.1

Perform the row operation

R_{3} = R_{3} - R_{1}

$R_{3} = R_{3} - R_{1}$ to make the entry at

3, 1

$3, 1$ a

0

$0$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 1 - 1 & 2 - 1 & 3 - 0 & 0 - \frac{1}{4} & 0 - 0 & 1 - 0 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 1 - 1 & 2 - 1 & 3 - 0 & 0 - \frac{1}{4} & 0 - 0 & 1 - 0 \end{array}]$

Langkah 4.3.2

Sederhanakan

R_{3}

$R_{3}$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 1 & 3 & - \frac{1}{4} & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 1 & 3 & - \frac{1}{4} & 0 & 1 \end{array}]$

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 1 & 3 & - \frac{1}{4} & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 1 & 3 & - \frac{1}{4} & 0 & 1 \end{array}]$

Langkah 4.4

Perform the row operation

R_{3} = R_{3} - R_{2}

$R_{3} = R_{3} - R_{2}$ to make the entry at

3, 2

$3, 2$ a

0

$0$ .

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Langkah 4.4.1

Perform the row operation

R_{3} = R_{3} - R_{2}

$R_{3} = R_{3} - R_{2}$ to make the entry at

3, 2

$3, 2$ a

0

$0$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 - 0 & 1 - 1 & 3 - 1 & - \frac{1}{4} + \frac{1}{2} & 0 - 1 & 1 - 0 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 - 0 & 1 - 1 & 3 - 1 & - \frac{1}{4} + \frac{1}{2} & 0 - 1 & 1 - 0 \end{array}]$

Langkah 4.4.2

Sederhanakan

R_{3}

$R_{3}$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 0 & 2 & \frac{1}{4} & - 1 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 0 & 2 & \frac{1}{4} & - 1 & 1 \end{array}]$

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 0 & 2 & \frac{1}{4} & - 1 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 0 & 2 & \frac{1}{4} & - 1 & 1 \end{array}]$

Langkah 4.5

Multiply each element of

R_{3}

$R_{3}$ by

\frac{1}{2}

$\frac{1}{2}$ to make the entry at

3, 3

$3, 3$ a

1

$1$ .

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Langkah 4.5.1

Multiply each element of

R_{3}

$R_{3}$ by

\frac{1}{2}

$\frac{1}{2}$ to make the entry at

3, 3

$3, 3$ a

1

$1$ .

⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \frac{0}{2} & \frac{0}{2} & \frac{2}{2} & \frac{\frac{1}{4}}{2} & \frac{- 1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ \frac{0}{2} & \frac{0}{2} & \frac{2}{2} & \frac{\frac{1}{4}}{2} & \frac{- 1}{2} & \frac{1}{2} \end{array}]$

Langkah 4.5.2

Sederhanakan

R_{3}

$R_{3}$ .

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 1 & - \frac{1}{2} & 1 & 0 \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

Langkah 4.6

Perform the row operation

$R_{2} = R_{2} - R_{3}$ to make the entry at

$2, 3$ a

$0$ .

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Langkah 4.6.1

Perform the row operation

$R_{2} = R_{2} - R_{3}$ to make the entry at

$2, 3$ a

$0$ .

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 - 0 & 1 - 0 & 1 - 1 & - \frac{1}{2} - \frac{1}{8} & 1 + \frac{1}{2} & 0 - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

Langkah 4.6.2

Sederhanakan

$R_{2}$ .

$[\begin{array}{c} 1 & 1 & 0 & \frac{1}{4} & 0 & 0 \\ 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

Langkah 4.7

Perform the row operation

$R_{1} = R_{1} - R_{2}$ to make the entry at

$1, 2$ a

$0$ .

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Langkah 4.7.1

Perform the row operation

$R_{1} = R_{1} - R_{2}$ to make the entry at

$1, 2$ a

$0$ .

$[\begin{array}{c} 1 - 0 & 1 - 1 & 0 - 0 & \frac{1}{4} + \frac{5}{8} & 0 - \frac{3}{2} & 0 + \frac{1}{2} \\ 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

Langkah 4.7.2

Sederhanakan

$R_{1}$ .

$[\begin{array}{c} 1 & 0 & 0 & \frac{7}{8} & - \frac{3}{2} & \frac{1}{2} \\ 0 & 1 & 0 & - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ 0 & 0 & 1 & \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

Langkah 5

The right half of the reduced row echelon form is the inverse.

$[\begin{array}{c} \frac{7}{8} & - \frac{3}{2} & \frac{1}{2} \\ - \frac{5}{8} & \frac{3}{2} & - \frac{1}{2} \\ \frac{1}{8} & - \frac{1}{2} & \frac{1}{2} \end{array}]$

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