Contoh

[\begin{array}{c} 1 & 4 & 5 & 0 \\ 0 & 2 & 1 & 3 \\ 2 & 5 & 4 & 1 \\ 1 & 5 & 0 & 2 \end{array}]

$[\begin{array}{c} 1 & 4 & 5 & 0 \\ 0 & 2 & 1 & 3 \\ 2 & 5 & 4 & 1 \\ 1 & 5 & 0 & 2 \end{array}]$

Langkah 1

Choose the row or column with the most

0

$0$ elements. If there are no

0

$0$ elements choose any row or column. Multiply every element in row

1

$1$ by its cofactor and add.

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Langkah 1.1

Consider the corresponding sign chart.

| \begin{array}{c} + & - & + & - \\ - & + & - & + \\ + & - & + & - \\ - & + & - & + \end{array} |

$| \begin{array}{c} + & - & + & - \\ - & + & - & + \\ + & - & + & - \\ - & + & - & + \end{array} |$

Langkah 1.2

The cofactor is the minor with the sign changed if the indices match a

-

$-$ position on the sign chart.

Langkah 1.3

The minor for

a_{11}

$a_{11}$ is the determinant with row

1

$1$ and column

1

$1$ deleted.

| \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} |

$| \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} |$

Langkah 1.4

Multiply element

a_{11}

$a_{11}$ by its cofactor.

1 | \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} |

$1 | \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} |$

Langkah 1.5

The minor for

a_{12}

$a_{12}$ is the determinant with row

1

$1$ and column

2

$2$ deleted.

| \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} |

$| \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} |$

Langkah 1.6

Multiply element

a_{12}

$a_{12}$ by its cofactor.

- 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} |

$- 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} |$

Langkah 1.7

The minor for

a_{13}

$a_{13}$ is the determinant with row

1

$1$ and column

3

$3$ deleted.

| \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} |

$| \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} |$

Langkah 1.8

Multiply element

a_{13}

$a_{13}$ by its cofactor.

5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} |

$5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} |$

Langkah 1.9

The minor for

a_{14}

$a_{14}$ is the determinant with row

1

$1$ and column

4

$4$ deleted.

| \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |

$| \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |$

Langkah 1.10

Multiply element

a_{14}

$a_{14}$ by its cofactor.

0 | \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |

$0 | \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |$

Langkah 1.11

Add the terms together.

1 | \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} | - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0 | \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |

$1 | \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} | - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0 | \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |$

1 | \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} | - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0 | \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |

Langkah 2

Kalikan

0

$0$ dengan

| \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |

$| \begin{array}{c} 0 & 2 & 1 \\ 2 & 5 & 4 \\ 1 & 5 & 0 \end{array} |$ .

1 | \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} | - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

Langkah 3

Evaluasi

| \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} |

$| \begin{array}{c} 2 & 1 & 3 \\ 5 & 4 & 1 \\ 5 & 0 & 2 \end{array} |$ .

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Langkah 3.1

Choose the row or column with the most

0

$0$ elements. If there are no

0

$0$ elements choose any row or column. Multiply every element in column

2

$2$ by its cofactor and add.

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Langkah 3.1.1

Consider the corresponding sign chart.

| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |

$| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |$

Langkah 3.1.2

The cofactor is the minor with the sign changed if the indices match a

-

$-$ position on the sign chart.

Langkah 3.1.3

The minor for

a_{12}

$a_{12}$ is the determinant with row

1

$1$ and column

2

$2$ deleted.

| \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |

$| \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |$

Langkah 3.1.4

Multiply element

a_{12}

$a_{12}$ by its cofactor.

- 1 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |

$- 1 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |$

Langkah 3.1.5

The minor for

a_{22}

$a_{22}$ is the determinant with row

2

$2$ and column

2

$2$ deleted.

| \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} |

$| \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} |$

Langkah 3.1.6

Multiply element

a_{22}

$a_{22}$ by its cofactor.

4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} |

$4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} |$

Langkah 3.1.7

The minor for

a_{32}

$a_{32}$ is the determinant with row

3

$3$ and column

2

$2$ deleted.

| \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |

$| \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |$

Langkah 3.1.8

Multiply element

a_{32}

$a_{32}$ by its cofactor.

0 | \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |

$0 | \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |$

Langkah 3.1.9

Add the terms together.

1 (- 1 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0 | \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0 | \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 (- 1 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0 | \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

Langkah 3.2

Kalikan

0

$0$ dengan

| \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |

$| \begin{array}{c} 2 & 3 \\ 5 & 1 \end{array} |$ .

1 (- 1 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.3

Evaluasi

| \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |

$| \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |$ .

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Langkah 3.3.1

Determinan dari matriks

2 \times 2

$2 \times 2$ dapat dicari menggunakan rumus

| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

1 (- 1 (5 \cdot 2 - 5 \cdot 1) + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 (5 \cdot 2 - 5 \cdot 1) + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.3.2

Sederhanakan determinannya.

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Langkah 3.3.2.1

Sederhanakan setiap suku.

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Langkah 3.3.2.1.1

Kalikan

5

$5$ dengan

2

$2$ .

1 (- 1 (10 - 5 \cdot 1) + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 (10 - 5 \cdot 1) + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.3.2.1.2

Kalikan

- 5

$- 5$ dengan

1

$1$ .

1 (- 1 (10 - 5) + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 (10 - 5) + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 (- 1 (10 - 5) + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

Langkah 3.3.2.2

Kurangi

5

$5$ dengan

10

$10$ .

1 (- 1 \cdot 5 + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 \cdot 5 + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 (- 1 \cdot 5 + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

1 (- 1 \cdot 5 + 4 | \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} | + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

Langkah 3.4

Evaluasi

| \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} |

$| \begin{array}{c} 2 & 3 \\ 5 & 2 \end{array} |$ .

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Langkah 3.4.1

Determinan dari matriks

2 \times 2

$2 \times 2$ dapat dicari menggunakan rumus

| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

1 (- 1 \cdot 5 + 4 (2 \cdot 2 - 5 \cdot 3) + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 \cdot 5 + 4 (2 \cdot 2 - 5 \cdot 3) + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.4.2

Sederhanakan determinannya.

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Langkah 3.4.2.1

Sederhanakan setiap suku.

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Langkah 3.4.2.1.1

Kalikan

2

$2$ dengan

2

$2$ .

1 (- 1 \cdot 5 + 4 (4 - 5 \cdot 3) + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 \cdot 5 + 4 (4 - 5 \cdot 3) + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.4.2.1.2

Kalikan

- 5

$- 5$ dengan

3

$3$ .

1 (- 1 \cdot 5 + 4 (4 - 15) + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 \cdot 5 + 4 (4 - 15) + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 (- 1 \cdot 5 + 4 (4 - 15) + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 \cdot 5 + 4 (4 - 15) + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.4.2.2

Kurangi

15

$15$ dengan

4

$4$ .

1 (- 1 \cdot 5 + 4 \cdot - 11 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 \cdot 5 + 4 \cdot - 11 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 (- 1 \cdot 5 + 4 \cdot - 11 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 \cdot 5 + 4 \cdot - 11 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 (- 1 \cdot 5 + 4 \cdot - 11 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 1 \cdot 5 + 4 \cdot - 11 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.5

Sederhanakan determinannya.

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Langkah 3.5.1

Sederhanakan setiap suku.

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Langkah 3.5.1.1

Kalikan

- 1

$- 1$ dengan

5

$5$ .

1 (- 5 + 4 \cdot - 11 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 5 + 4 \cdot - 11 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.5.1.2

Kalikan

4

$4$ dengan

- 11

$- 11$ .

1 (- 5 - 44 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 5 - 44 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 (- 5 - 44 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 5 - 44 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.5.2

Kurangi

44

$44$ dengan

- 5

$- 5$ .

1 (- 49 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 (- 49 + 0) - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 3.5.3

Tambahkan

- 49

$- 49$ dan

0

$0$ .

1 \cdot - 49 - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 | \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} | + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4

Evaluasi

| \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} |

$| \begin{array}{c} 0 & 1 & 3 \\ 2 & 4 & 1 \\ 1 & 0 & 2 \end{array} |$ .

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Langkah 4.1

Choose the row or column with the most

0

$0$ elements. If there are no

0

$0$ elements choose any row or column. Multiply every element in row

1

$1$ by its cofactor and add.

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Langkah 4.1.1

Consider the corresponding sign chart.

| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |

$| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |$

Langkah 4.1.2

The cofactor is the minor with the sign changed if the indices match a

-

$-$ position on the sign chart.

Langkah 4.1.3

The minor for

a_{11}

$a_{11}$ is the determinant with row

1

$1$ and column

1

$1$ deleted.

| \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} |

$| \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} |$

Langkah 4.1.4

Multiply element

a_{11}

$a_{11}$ by its cofactor.

0 | \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} |

$0 | \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} |$

Langkah 4.1.5

The minor for

a_{12}

$a_{12}$ is the determinant with row

1

$1$ and column

2

$2$ deleted.

| \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |

$| \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |$

Langkah 4.1.6

Multiply element

a_{12}

$a_{12}$ by its cofactor.

- 1 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |

$- 1 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |$

Langkah 4.1.7

The minor for

a_{13}

$a_{13}$ is the determinant with row

1

$1$ and column

3

$3$ deleted.

| \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |

$| \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |$

Langkah 4.1.8

Multiply element

a_{13}

$a_{13}$ by its cofactor.

3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |

$3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |$

Langkah 4.1.9

Add the terms together.

1 \cdot - 49 - 4 (0 | \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} | - 1 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 | \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} | - 1 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 (0 | \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} | - 1 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

Langkah 4.2

Kalikan

0

$0$ dengan

| \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} |

$| \begin{array}{c} 4 & 1 \\ 0 & 2 \end{array} |$ .

1 \cdot - 49 - 4 (0 - 1 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.3

Evaluasi

| \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |

$| \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |$ .

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Langkah 4.3.1

Determinan dari matriks

2 \times 2

$2 \times 2$ dapat dicari menggunakan rumus

| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

1 \cdot - 49 - 4 (0 - 1 (2 \cdot 2 - 1 \cdot 1) + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 (2 \cdot 2 - 1 \cdot 1) + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.3.2

Sederhanakan determinannya.

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Langkah 4.3.2.1

Sederhanakan setiap suku.

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Langkah 4.3.2.1.1

Kalikan

2

$2$ dengan

2

$2$ .

1 \cdot - 49 - 4 (0 - 1 (4 - 1 \cdot 1) + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 (4 - 1 \cdot 1) + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.3.2.1.2

Kalikan

- 1

$- 1$ dengan

1

$1$ .

1 \cdot - 49 - 4 (0 - 1 (4 - 1) + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 (4 - 1) + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 (0 - 1 (4 - 1) + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 (4 - 1) + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.3.2.2

Kurangi

1

$1$ dengan

4

$4$ .

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 | \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.4

Evaluasi

| \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |

$| \begin{array}{c} 2 & 4 \\ 1 & 0 \end{array} |$ .

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Langkah 4.4.1

Determinan dari matriks

2 \times 2

$2 \times 2$ dapat dicari menggunakan rumus

| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 (2 \cdot 0 - 1 \cdot 4)) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 (2 \cdot 0 - 1 \cdot 4)) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.4.2

Sederhanakan determinannya.

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Langkah 4.4.2.1

Sederhanakan setiap suku.

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Langkah 4.4.2.1.1

Kalikan

2

$2$ dengan

0

$0$ .

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 (0 - 1 \cdot 4)) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 (0 - 1 \cdot 4)) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.4.2.1.2

Kalikan

- 1

$- 1$ dengan

4

$4$ .

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 (0 - 4)) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 (0 - 4)) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 (0 - 4)) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 (0 - 4)) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.4.2.2

Kurangi

4

$4$ dengan

0

$0$ .

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 \cdot - 4) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 \cdot - 4) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 \cdot - 4) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 \cdot - 4) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 \cdot - 4) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 1 \cdot 3 + 3 \cdot - 4) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.5

Sederhanakan determinannya.

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Langkah 4.5.1

Sederhanakan setiap suku.

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Langkah 4.5.1.1

Kalikan

- 1

$- 1$ dengan

3

$3$ .

1 \cdot - 49 - 4 (0 - 3 + 3 \cdot - 4) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 3 + 3 \cdot - 4) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.5.1.2

Kalikan

3

$3$ dengan

- 4

$- 4$ .

1 \cdot - 49 - 4 (0 - 3 - 12) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 3 - 12) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 (0 - 3 - 12) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (0 - 3 - 12) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.5.2

Kurangi

3

$3$ dengan

0

$0$ .

1 \cdot - 49 - 4 (- 3 - 12) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 (- 3 - 12) + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 4.5.3

Kurangi

12

$12$ dengan

- 3

$- 3$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 | \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} | + 0$

Langkah 5

Evaluasi

| \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} |

$| \begin{array}{c} 0 & 2 & 3 \\ 2 & 5 & 1 \\ 1 & 5 & 2 \end{array} |$ .

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Langkah 5.1

Choose the row or column with the most

0

$0$ elements. If there are no

0

$0$ elements choose any row or column. Multiply every element in row

1

$1$ by its cofactor and add.

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Langkah 5.1.1

Consider the corresponding sign chart.

| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |

$| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |$

Langkah 5.1.2

The cofactor is the minor with the sign changed if the indices match a

-

$-$ position on the sign chart.

Langkah 5.1.3

The minor for

a_{11}

$a_{11}$ is the determinant with row

1

$1$ and column

1

$1$ deleted.

| \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |

$| \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |$

Langkah 5.1.4

Multiply element

a_{11}

$a_{11}$ by its cofactor.

0 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |

$0 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |$

Langkah 5.1.5

The minor for

a_{12}

$a_{12}$ is the determinant with row

1

$1$ and column

2

$2$ deleted.

| \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |

$| \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |$

Langkah 5.1.6

Multiply element

a_{12}

$a_{12}$ by its cofactor.

- 2 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |

$- 2 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |$

Langkah 5.1.7

The minor for

a_{13}

$a_{13}$ is the determinant with row

1

$1$ and column

3

$3$ deleted.

| \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |

$| \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |$

Langkah 5.1.8

Multiply element

a_{13}

$a_{13}$ by its cofactor.

3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |

$3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |$

Langkah 5.1.9

Add the terms together.

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | - 2 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | - 2 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | - 2 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 | \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} | - 2 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

Langkah 5.2

Kalikan

0

$0$ dengan

| \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |

$| \begin{array}{c} 5 & 1 \\ 5 & 2 \end{array} |$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 | \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} | + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

Langkah 5.3

Evaluasi

| \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |

$| \begin{array}{c} 2 & 1 \\ 1 & 2 \end{array} |$ .

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Langkah 5.3.1

Determinan dari matriks

2 \times 2

$2 \times 2$ dapat dicari menggunakan rumus

| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 (2 \cdot 2 - 1 \cdot 1) + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 (2 \cdot 2 - 1 \cdot 1) + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

Langkah 5.3.2

Sederhanakan determinannya.

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Langkah 5.3.2.1

Sederhanakan setiap suku.

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Langkah 5.3.2.1.1

Kalikan

2

$2$ dengan

2

$2$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 (4 - 1 \cdot 1) + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 (4 - 1 \cdot 1) + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

Langkah 5.3.2.1.2

Kalikan

- 1

$- 1$ dengan

1

$1$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 (4 - 1) + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 (4 - 1) + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 (4 - 1) + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 (4 - 1) + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

Langkah 5.3.2.2

Kurangi

1

$1$ dengan

4

$4$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 | \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |) + 0$

Langkah 5.4

Evaluasi

| \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |

$| \begin{array}{c} 2 & 5 \\ 1 & 5 \end{array} |$ .

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Langkah 5.4.1

Determinan dari matriks

2 \times 2

$2 \times 2$ dapat dicari menggunakan rumus

| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 (2 \cdot 5 - 1 \cdot 5)) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 (2 \cdot 5 - 1 \cdot 5)) + 0$

Langkah 5.4.2

Sederhanakan determinannya.

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Langkah 5.4.2.1

Sederhanakan setiap suku.

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Langkah 5.4.2.1.1

Kalikan

2

$2$ dengan

5

$5$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 (10 - 1 \cdot 5)) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 (10 - 1 \cdot 5)) + 0$

Langkah 5.4.2.1.2

Kalikan

- 1

$- 1$ dengan

5

$5$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 (10 - 5)) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 (10 - 5)) + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 (10 - 5)) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 (10 - 5)) + 0$

Langkah 5.4.2.2

Kurangi

5

$5$ dengan

10

$10$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 \cdot 5) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 \cdot 5) + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 \cdot 5) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 \cdot 5) + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 \cdot 5) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 2 \cdot 3 + 3 \cdot 5) + 0$

Langkah 5.5

Sederhanakan determinannya.

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Langkah 5.5.1

Sederhanakan setiap suku.

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Langkah 5.5.1.1

Kalikan

- 2

$- 2$ dengan

3

$3$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 6 + 3 \cdot 5) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 6 + 3 \cdot 5) + 0$

Langkah 5.5.1.2

Kalikan

3

$3$ dengan

5

$5$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 6 + 15) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 6 + 15) + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 6 + 15) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (0 - 6 + 15) + 0$

Langkah 5.5.2

Kurangi

6

$6$ dengan

0

$0$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 (- 6 + 15) + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 (- 6 + 15) + 0$

Langkah 5.5.3

Tambahkan

- 6

$- 6$ dan

15

$15$ .

1 \cdot - 49 - 4 \cdot - 15 + 5 \cdot 9 + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 \cdot 9 + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 \cdot 9 + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 \cdot 9 + 0$

1 \cdot - 49 - 4 \cdot - 15 + 5 \cdot 9 + 0

$1 \cdot - 49 - 4 \cdot - 15 + 5 \cdot 9 + 0$

Langkah 6

Sederhanakan determinannya.

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Langkah 6.1

Sederhanakan setiap suku.

Ketuk untuk lebih banyak langkah...

Langkah 6.1.1

Kalikan

- 49

$- 49$ dengan

1

$1$ .

- 49 - 4 \cdot - 15 + 5 \cdot 9 + 0

$- 49 - 4 \cdot - 15 + 5 \cdot 9 + 0$

Langkah 6.1.2

Kalikan

- 4

$- 4$ dengan

- 15

$- 15$ .

- 49 + 60 + 5 \cdot 9 + 0

$- 49 + 60 + 5 \cdot 9 + 0$

Langkah 6.1.3

Kalikan

5

$5$ dengan

9

$9$ .

- 49 + 60 + 45 + 0

$- 49 + 60 + 45 + 0$

- 49 + 60 + 45 + 0

$- 49 + 60 + 45 + 0$

Langkah 6.2

Tambahkan

- 49

$- 49$ dan

60

$60$ .

11 + 45 + 0

$11 + 45 + 0$

Langkah 6.3

Tambahkan

11

$11$ dan

45

$45$ .

56 + 0

$56 + 0$

Langkah 6.4

Tambahkan

56

$56$ dan

0

$0$ .

56

$56$

56

$56$

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