Mathway | प्रचलित समस्याएं

प्रचलित समस्याएं

रैंक	विषय	समस्या	फॉर्मेट की गई समस्या
2301	शेष	NaHCO_3+HCl→CO_2+NaCl+H_2O	$N a H C O_{3} + H C l \to C O_{2} + N a C l + H_{2} O$
2302	शेष	NaHCO_3+HCl→NaCL+CO_2+H_2O	$N a H C O_{3} + H C l \to N a C L + C O_{2} + H_{2} O$
2303	शेष	NaHCO_3+HCl=NaCl+H_2O+CO_2	$N a H C O_{3} + H C l = N a C l + H_{2} O + C O_{2}$
2304	शेष	NaHCO_3=Na_2CO_3+CO_2+H_2O	$N a H C O_{3} = N a_{2} C O_{3} + C O_{2} + H_{2} O$
2305	शेष	NaHCO_3=Na_2CO_3+H_2O+CO_2	$N a H C O_{3} = N a_{2} C O_{3} + H_{2} O + C O_{2}$
2306	शेष	NaHNO_3→CO_2+NaOH	$N a H N O_{3} \to C O_{2} + N a O H$
2307	शेष	NaI+Cl_2→NaCl+I	$N a I + C l_{2} \to N a C l + I$
2308	सान्द्रता ज्ञात कीजिये	number (of)(mol)(of)(solute)in300(mL)(of)4.00M(solution)	number $(o f) (m o l e s) (o f) (s o l u t e) i n \cdot 300 (mL) (o f) \cdot 4 M (s o l u t i o n)$
2309	शेष	NaN_3→Na+N	$N a N_{3} \to N a + N$
2310	शेष	MnO_2+H_2C_2O_4+H_2SO_4→MnSO_4+CO_2+H_2O	$M n O_{2} + H_{2} C_{2} O_{4} + H_{2} S O_{4} \to M n S O_{4} + C O_{2} + H_{2} O$
2311	शेष	Na_2O+P_4O_10=NA_3PO_4	$N a_{2} O + P_{4} O_{10} = N A_{3} P O_{4}$
2312	शेष	Na_2O_2+H_2O→NaOH+O_2	$N a_{2} O_{2} + H_{2} O \to N a O H + O_{2}$
2313	शेष	Na_2S_2O_3+AgBr→NaBr+Ag_2S_2O_3	$N a_{2} S_{2} O_{3} + A g B r \to N a B r + A g_{2} S_{2} O_{3}$
2314	शेष	Na_2SiO_3(s)+8HF(aq)→H_2SiF_6(aq)+2NaF(aq)+3H_2O(l)	$N a_{2} S i O_{3} (s) + 8 H F (a q) \to H_{2} S i F_{6} (a q) + 2 N a F (a q) + 3 H_{2} O (l)$
2315	शेष	Na_2SO_3+HCl→NaCl+H_2O+SO_2	$N a_{2} S O_{3} + H C l \to N a C l + H_{2} O + S O_{2}$
2316	शेष	Na_3(PO_4)+NiCl→NaCl+Ni_3(PO_4)_2	$N a_{3} (P O_{4}) + N i C l \to N a C l + N i_{3} {(P O_{4})}_{2}$
2317	शेष	Na_3P→Na+P	$N a_{3} P \to N a + P$
2318	शेष	Na_3PO_4+CaCl_2→Ca_3P_2O_8+NaCl	$N a_{3} P O_{4} + C a C l_{2} \to C a_{3} P_{2} O_{8} + N a C l$
2319	शेष	Na_3Po_4+Mg_3Cl_2→Mg_3(PO_4)_2+NaCl	$N a_{3} P o_{4} + M g_{3} C l_{2} \to M g_{3} {(P O_{4})}_{2} + N a C l$
2320	शेष	NaBH_4+BF_4→NaBF_4+B_2H_6	$N a B H_{4} + B F_{4} \to N a B F_{4} + B_{2} H_{6}$
2321	शेष	NaBr+I_2=NaI+Br_2	$N a B r + I_{2} = N a I + B r_{2}$
2322	शेष	Na+O_2→NaO	$N a + O_{2} \to N a O$
2323	शेष	Na+O_2→NaO_2	$N a + O_{2} \to N a O_{2}$
2324	शेष	Na+O_2=Na_2O	$N a + O_{2} = N a_{2} O$
2325	शेष	Na+OH→NaOH	$N a + O H \to N a O H$
2326	शेष	Na+Pb(NO_3)_2→NNO_3+Pb	$N a + P b {(N O_{3})}_{2} \to N N O_{3} + P b$
2327	शेष	Na_2+H_2O→HNa+O	$N a_{2} + H_{2} O \to H N a + O$
2328	शेष	Na_2C_2O_4+Ca(NO_3)_2→Na(NO_3)_2+CaC_2O_4	$N a_{2} C_{2} O_{4} + C a {(N O_{3})}_{2} \to N a {(N O_{3})}_{2} + C a C_{2} O_{4}$
2329	शेष	Na_2CO_3→Na_2O+CO_2	$N a_{2} C O_{3} \to N a_{2} O + C O_{2}$
2330	शेष	Na_2HPO_4→Na_4P_2O_7+H_2O	$N a_{2} H P O_{4} \to N a_{4} P_{2} O_{7} + H_{2} O$
2331	शेष	NaCl+H_2SO_4→HCI+NaHSO_4	$N a C l + H_{2} S O_{4} \to H C I + N a H S O_{4}$
2332	शेष	NaCl+H_2SO_4→NaSO_4+HCl	$N a C l + H_{2} S O_{4} \to N a S O_{4} + H C l$
2333	शेष	NaCl+HgNO_3→AgCl+NaNO_3	$N a C l + H g N O_{3} \to A g C l + N a N O_{3}$
2334	शेष	NaCl+KNO_3→NaNO_3+KCl	$N a C l + K N O_{3} \to N a N O_{3} + K C l$
2335	शेष	NaCl+SO_2+H_2O+O_2→Na_2SO_4+HCl	$N a C l + S O_{2} + H_{2} O + O_{2} \to N a_{2} S O_{4} + H C l$
2336	शेष	NaCIO_3→NaCI+O_2	$N a C I O_{3} \to N a C I + O_{2}$
2337	शेष	Na+N_2→Na_3N	$N a + N_{2} \to N a_{3} N$
2338	शेष	Ni(ClO_3)_2→NiCl_2+O_2	$N i {(C l O_{3})}_{2} \to N i C l_{2} + O_{2}$
2339	शेष	Ni(CO)_4→4CO+Ni	$N i {(C O)}_{4} \to 4 C O + N i$
2340	शेष	NiS+O_2=NiO+SO_2	$N i S + O_{2} = N i O + S O_{2}$
2341	शेष	NO_2+H_2O→HNO_3	$N O_{2} + H_{2} O \to H N O_{3}$
2342	शेष	NO_2+Pb_2O_4=N_2+PbO_8	$N O_{2} + P b_{2} O_{4} = N_{2} + P b O_{8}$
2343	शेष	O_2+CH_4→CO_2+H_2O	$O_{2} + C H_{4} \to C O_{2} + H_{2} O$
2344	शेष	O_2+CH_4→H_2O+CO	$O_{2} + C H_{4} \to H_{2} O + C O$
2345	शेष	O+Mg→MgO	$O + M g \to M g O$
2346	शेष	O_2+C_6H_12O_6→CO_2+H_2O	$O_{2} + C_{6} H_{12} O_{6} \to C O_{2} + H_{2} O$
2347	शेष	O_2+Sb→H_2O_2+SbO_2	$O_{2} + S b \to H_{2} O_{2} + S b O_{2}$
2348	अाक्सीकरण संख्याएँ ज्ञात कीजिये	Mn(ClO_4)_3	$M n {(C l O_{4})}_{3}$
2349	शेष	NaOH+H_2SO_4=NaSO_4+H_2O	$N a O H + H_{2} S O_{4} = N a S O_{4} + H_{2} O$
2350	शेष	NaOH+HCl→NaCl+H_2O	$N a O H + H C l \to N a C l + H_{2} O$
2351	शेष	NaOH+Mg(NO_3)_2→NaNO_3+Mg(OH)_2	$N a O H + M g {(N O_{3})}_{2} \to N a N O_{3} + M g {(O H)}_{2}$
2352	शेष	NaOH+Pb(NO_3)_2→Pb(OH)_4+NaNO_3	$N a O H + P b {(N O_{3})}_{2} \to P b {(O H)}_{4} + N a N O_{3}$
2353	शेष	NaSiO_3+8HF→H_2SiF_6+2NaF+3H_2O	$N a S i O_{3} + 8 H F \to H_{2} S i F_{6} + 2 N a F + 3 H_{2} O$
2354	शेष	NBr_3+NaOH→N_2+NaBr+HOBr	$N B r_{3} + N a O H \to N_{2} + N a B r + H O B r$
2355	शेष	NCl_3+H_2O→NH_3+HOCl	$N C l_{3} + H_{2} O \to N H_{3} + H O C l$
2356	शेष	C_6H_12+O_2=H_2O+H_2C_6H_8O_4	$C_{6} H_{12} + O_{2} = H_{2} O + H_{2} C_{6} H_{8} O_{4}$
2357	शेष	NH_3+Mg→MgN+H_2	$N H_{3} + M g \to M g N + H_{2}$
2358	शेष	NH_3+H_2O→NH_4+OH	$N H_{3} + H_{2} O \to N H_{4} + O H$
2359	शेष	NH_3+H_2SO_4→N_2H_8SO_4	$N H_{3} + H_{2} S O_{4} \to N_{2} H_{8} S O_{4}$
2360	शेष	NH_3(g)+O_2(g)→NO(g)+H_2O(l)	$N H_{3} (g) + O_{2} (g) \to N O (g) + H_{2} O (l)$
2361	शेष	NH_3+O_2→N_2O_4+H_2O	$N H_{3} + O_{2} \to N_{2} O_{4} + H_{2} O$
2362	शेष	NaNO_3+H_2O→NaOH+HNO_3	$N a N O_{3} + H_{2} O \to N a O H + H N O_{3}$
2363	शेष	NaO_2+H_2SO_4→NaSO_4+H_2O_2	$N a O_{2} + H_{2} S O_{4} \to N a S O_{4} + H_{2} O_{2}$
2364	शेष	(sec(T))(csc(T))=2(csc(T))	$(\sec (T)) (\csc (T)) = 2 (\csc (T))$
2365	शेष	MG+N_2→MG_3N_2	$M G + N_{2} \to M G_{3} N_{2}$
2366	शेष	Mg+NaF→MgF_2+Na	$M g + N a F \to M g F_{2} + N a$
2367	शेष	Mg+NaHO→Na+MgO+H	$M g + N a H O \to N a + M g O + H$
2368	शेष	Mg+Hg→MgHg	$M g + H g \to M g H g$
2369	शेष	Li_20+Zr_30→Li_40Zr_80	$L i_{20} + Z r_{30} \to L i_{40} Z r_{80}$
2370	शेष	HCl+CaOH→CaCl_2+H_2O	$H C l + C a O H \to C a C l_{2} + H_{2} O$
2371	शेष	Mg+Cu→Mg+Cu	$M g + C u \to M g + C u$
2372	शेष	Mg+Fe_2O_3→Fe+MgO	$M g + F e_{2} O_{3} \to F e + M g O$
2373	शेष	Mg+H_2SO_4→MgH_2SO_4+OH_2	$M g + H_{2} S O_{4} \to M g H_{2} S O_{4} + O H_{2}$
2374	शेष	Mg+H_3PO_4→Mg_3(PO_4)_2+H_2	$M g + H_{3} P O_{4} \to M g_{3} {(P O_{4})}_{2} + H_{2}$
2375	सान्द्रता ज्ञात कीजिये	Calculate the molarity of 0.754molKNO_3 in 225mL	Calculate the molarity of $0.754$ mol $K N O_{3}$ in $225 mL$
2376	शेष	Mg+H_2Sn_4→MgSO_4+H_2O	$M g + H_{2} S n_{4} \to M g S O_{4} + H_{2} O$
2377	शेष	Mg+HCI→MgCl_2+H	$M g + H C I \to M g C l_{2} + H$
2378	शेष	Mg+HCl→Mg	$M g + H C l \to M g$
2379	शेष	Mg+HCl→MgCl+H	$M g + H C l \to M g C l + H$
2380	शेष	Mg+HCl→MgCl_2+H	$M g + H C l \to M g C l_{2} + H$
2381	शेष	Mg_3N_2+H_2O→MgO+NH_3	$M g_{3} N_{2} + H_{2} O \to M g O + N H_{3}$
2382	शेष	Mg+2HCI→MgCI+H_2	$M g + 2 H C I \to M g C I + H_{2}$
2383	शेष	Mg+2HCl→MgCl_2+H_2	$M g + 2 H C l \to M g C l_{2} + H_{2}$
2384	शेष	Mg+Cl→Mg	$M g + C l \to M g$
2385	शेष	Mg+Cl→MgCl	$M g + C l \to M g C l$
2386	शेष	Mg+Zn(NO_3)_2→Mg(NO_3)_2+Zn	$M g + Z n {(N O_{3})}_{2} \to M g {(N O_{3})}_{2} + Z n$
2387	शेष	Mg_3P_2+Na_2O=MgO+Na	$M g_{3} P_{2} + N a_{2} O = M g O + N a$
2388	शेष	MgBr_2+Cl→MgCl+Br	$M g B r_{2} + C l \to M g C l + B r$
2389	शेष	MgCl_2+Ca(OH)_2→CaCl+Mg(OH)_2	$M g C l_{2} + C a {(O H)}_{2} \to C a C l + M g {(O H)}_{2}$
2390	शेष	MgCl_2+NaOH→Mg(OH)_2+NaCl	$M g C l_{2} + N a O H \to M g {(O H)}_{2} + N a C l$
2391	शेष	MgF_2→Mg+F	$M g F_{2} \to M g + F$
2392	शेष	MgF_2+K=Mg+KF	$M g F_{2} + K = M g + K F$
2393	शेष	MgNH_4PO_4+6H_2O→MgNH_4PO_4	$M g N H_{4} P O_{4} + 6 H_{2} O \to M g N H_{4} P O_{4}$
2394	शेष	MgNH_4PO_4→Mg_2P_2O_7+NH_3+H_2O	$M g N H_{4} P O_{4} \to M g_{2} P_{2} O_{7} + N H_{3} + H_{2} O$
2395	शेष	a=n के लघुगणक	$\log (a) = n$
2396	शेष	MgO→Mg+O_2	$M g O \to M g + O_{2}$
2397	शेष	MgO+H_2O→MgOH	$M g O + H_{2} O \to M g O H$
2398	शेष	MgO_2H_2+HBr→MgBr_2+H_2O	$M g O_{2} H_{2} + H B r \to M g B r_{2} + H_{2} O$
2399	शेष	MgOH+HCl→MgCl+H_2O	$M g O H + H C l \to M g C l + H_{2} O$
2400	शेष	MnCl_2+Br_2+NH_4OH=MnO_2+H_4Cl+H_4Br+H_2O	$M n C l_{2} + B r_{2} + N H_{4} O H = M n O_{2} + H_{4} C l + H_{4} B r + H_{2} O$