Examples

[\begin{matrix} 2 & 4 6 & 8 \end{matrix}] - [\begin{matrix} 1 & 2 3 & 4 \end{matrix}]

$[\begin{array}{c} 2 & 4 \\ 6 & 8 \end{array}] - [\begin{array}{c} 1 & 2 \\ 3 & 4 \end{array}]$

Step 1

Subtract the corresponding elements.

[\begin{matrix} 2 - 1 & 4 - 2 6 - 3 & 8 - 4 \end{matrix}]

$[\begin{array}{c} 2 - 1 & 4 - 2 \\ 6 - 3 & 8 - 4 \end{array}]$

Step 2

Simplify each element.

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Step 2.1

Subtract

1

$1$ from

2

$2$ .

[\begin{matrix} 1 & 4 - 2 6 - 3 & 8 - 4 \end{matrix}]

$[\begin{array}{c} 1 & 4 - 2 \\ 6 - 3 & 8 - 4 \end{array}]$

Step 2.2

Subtract

2

$2$ from

4

$4$ .

[\begin{matrix} 1 & 2 6 - 3 & 8 - 4 \end{matrix}]

$[\begin{array}{c} 1 & 2 \\ 6 - 3 & 8 - 4 \end{array}]$

Step 2.3

Subtract

3

$3$ from

6

$6$ .

[\begin{matrix} 1 & 2 3 & 8 - 4 \end{matrix}]

$[\begin{array}{c} 1 & 2 \\ 3 & 8 - 4 \end{array}]$

Step 2.4

Subtract

4

$4$ from

8

$8$ .

[\begin{matrix} 1 & 2 3 & 4 \end{matrix}]

$[\begin{array}{c} 1 & 2 \\ 3 & 4 \end{array}]$

[\begin{matrix} 1 & 2 3 & 4 \end{matrix}]

$[\begin{array}{c} 1 & 2 \\ 3 & 4 \end{array}]$

Step 3

The determinant of a

2 \times 2

$2 \times 2$ matrix can be found using the formula

∣ ∣ ∣ \begin{matrix} a & b c & d \end{matrix} ∣ ∣ ∣ = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

1 \cdot 4 - 3 \cdot 2

$1 \cdot 4 - 3 \cdot 2$

Step 4

Simplify the determinant.

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Step 4.1

Simplify each term.

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Step 4.1.1

Multiply

4

$4$ by

1

$1$ .

4 - 3 \cdot 2

$4 - 3 \cdot 2$

Step 4.1.2

Multiply

- 3

$- 3$ by

2

$2$ .

4 - 6

$4 - 6$

4 - 6

$4 - 6$

Step 4.2

Subtract

6

$6$ from

4

$4$ .

- 2

$- 2$

- 2

$- 2$

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