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Examples

y = 2 x + 7

$y = 2 x + 7$

Step 1

Choose any value for

x

$x$ that is in the domain to plug into the equation.

Step 2

Choose

0

$0$ to substitute in for

x

$x$ to find the ordered pair.

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Step 2.1

Remove parentheses.

y = 2 (0) + 7

$y = 2 (0) + 7$

Step 2.2

Simplify

2 (0) + 7

$2 (0) + 7$ .

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Step 2.2.1

Multiply

2

$2$ by

0

$0$ .

y = 0 + 7

$y = 0 + 7$

Step 2.2.2

Add

0

$0$ and

7

$7$ .

y = 7

$y = 7$

y = 7

$y = 7$

Step 2.3

Use the

x

$x$ and

y

$y$ values to form the ordered pair.

(0, 7)

$(0, 7)$

(0, 7)

$(0, 7)$

Step 3

Choose

1

$1$ to substitute in for

x

$x$ to find the ordered pair.

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Step 3.1

Remove parentheses.

y = 2 (1) + 7

$y = 2 (1) + 7$

Step 3.2

Simplify

2 (1) + 7

$2 (1) + 7$ .

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Step 3.2.1

Multiply

2

$2$ by

1

$1$ .

y = 2 + 7

$y = 2 + 7$

Step 3.2.2

Add

2

$2$ and

7

$7$ .

y = 9

$y = 9$

y = 9

$y = 9$

Step 3.3

Use the

x

$x$ and

y

$y$ values to form the ordered pair.

(1, 9)

$(1, 9)$

(1, 9)

$(1, 9)$

Step 4

Choose

2

$2$ to substitute in for

x

$x$ to find the ordered pair.

Tap for more steps...

Step 4.1

Remove parentheses.

y = 2 (2) + 7

$y = 2 (2) + 7$

Step 4.2

Simplify

2 (2) + 7

$2 (2) + 7$ .

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Step 4.2.1

Multiply

2

$2$ by

2

$2$ .

y = 4 + 7

$y = 4 + 7$

Step 4.2.2

Add

4

$4$ and

7

$7$ .

y = 11

$y = 11$

y = 11

$y = 11$

Step 4.3

Use the

x

$x$ and

y

$y$ values to form the ordered pair.

(2, 11)

$(2, 11)$

(2, 11)

$(2, 11)$

Step 5

These are three possible solutions to the equation.

(0, 7), (1, 9), (2, 11)

$(0, 7), (1, 9), (2, 11)$

Step 6

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⎡ ⎢ ⎣ \begin{matrix} x^{2} & \frac{1}{2} \sqrt{π} & \int x d x \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$