Examples
6x3+4x2−xx2−4
Step 1
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 0.
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 |
Step 2
Divide the highest order term in the dividend 6x3 by the highest order term in divisor x2.
6x | |||||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 |
Step 3
Multiply the new quotient term by the divisor.
6x | |||||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 | ||
+ | 6x3 | + | 0 | - | 24x |
Step 4
The expression needs to be subtracted from the dividend, so change all the signs in 6x3+0−24x
6x | |||||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 | ||
- | 6x3 | - | 0 | + | 24x |
Step 5
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
6x | |||||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 | ||
- | 6x3 | - | 0 | + | 24x | ||||||||
+ | 4x2 | + | 23x |
Step 6
Pull the next terms from the original dividend down into the current dividend.
6x | |||||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 | ||
- | 6x3 | - | 0 | + | 24x | ||||||||
+ | 4x2 | + | 23x | + | 0 |
Step 7
Divide the highest order term in the dividend 4x2 by the highest order term in divisor x2.
6x | + | 4 | |||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 | ||
- | 6x3 | - | 0 | + | 24x | ||||||||
+ | 4x2 | + | 23x | + | 0 |
Step 8
Multiply the new quotient term by the divisor.
6x | + | 4 | |||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 | ||
- | 6x3 | - | 0 | + | 24x | ||||||||
+ | 4x2 | + | 23x | + | 0 | ||||||||
+ | 4x2 | + | 0 | - | 16 |
Step 9
The expression needs to be subtracted from the dividend, so change all the signs in 4x2+0−16
6x | + | 4 | |||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 | ||
- | 6x3 | - | 0 | + | 24x | ||||||||
+ | 4x2 | + | 23x | + | 0 | ||||||||
- | 4x2 | - | 0 | + | 16 |
Step 10
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
6x | + | 4 | |||||||||||
x2 | + | 0x | - | 4 | 6x3 | + | 4x2 | - | x | + | 0 | ||
- | 6x3 | - | 0 | + | 24x | ||||||||
+ | 4x2 | + | 23x | + | 0 | ||||||||
- | 4x2 | - | 0 | + | 16 | ||||||||
+ | 23x | + | 16 |
Step 11
The final answer is the quotient plus the remainder over the divisor.
6x+4+23x+16x2−4