Examples

|2y|+3=2+3|2y|+3=2+3
Step 1
Add 22 and 33.
|2y|+3=5|2y|+3=5
Step 2
Move all terms not containing |2y||2y| to the right side of the equation.
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Step 2.1
Subtract 33 from both sides of the equation.
|2y|=5-3|2y|=53
Step 2.2
Subtract 33 from 55.
|2y|=2|2y|=2
|2y|=2|2y|=2
Step 3
Remove the absolute value term. This creates a ±± on the right side of the equation because |x|=±x|x|=±x.
2y=±22y=±2
Step 4
The complete solution is the result of both the positive and negative portions of the solution.
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Step 4.1
First, use the positive value of the ±± to find the first solution.
2y=22y=2
Step 4.2
Divide each term in 2y=22y=2 by 22 and simplify.
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Step 4.2.1
Divide each term in 2y=22y=2 by 22.
2y2=222y2=22
Step 4.2.2
Simplify the left side.
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Step 4.2.2.1
Cancel the common factor of 22.
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Step 4.2.2.1.1
Cancel the common factor.
2y2=22
Step 4.2.2.1.2
Divide y by 1.
y=22
y=22
y=22
Step 4.2.3
Simplify the right side.
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Step 4.2.3.1
Divide 2 by 2.
y=1
y=1
y=1
Step 4.3
Next, use the negative value of the ± to find the second solution.
2y=-2
Step 4.4
Divide each term in 2y=-2 by 2 and simplify.
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Step 4.4.1
Divide each term in 2y=-2 by 2.
2y2=-22
Step 4.4.2
Simplify the left side.
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Step 4.4.2.1
Cancel the common factor of 2.
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Step 4.4.2.1.1
Cancel the common factor.
2y2=-22
Step 4.4.2.1.2
Divide y by 1.
y=-22
y=-22
y=-22
Step 4.4.3
Simplify the right side.
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Step 4.4.3.1
Divide -2 by 2.
y=-1
y=-1
y=-1
Step 4.5
The complete solution is the result of both the positive and negative portions of the solution.
y=1,-1
y=1,-1
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 [x2  12  π  xdx ] 
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