Trigonometry Examples

2sin(x)-1=02sin(x)1=0
Step 1
Add 11 to both sides of the equation.
2sin(x)=12sin(x)=1
Step 2
Divide each term in 2sin(x)=12sin(x)=1 by 22 and simplify.
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Step 2.1
Divide each term in 2sin(x)=12sin(x)=1 by 22.
2sin(x)2=122sin(x)2=12
Step 2.2
Simplify the left side.
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Step 2.2.1
Cancel the common factor of 22.
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Step 2.2.1.1
Cancel the common factor.
2sin(x)2=12
Step 2.2.1.2
Divide sin(x) by 1.
sin(x)=12
sin(x)=12
sin(x)=12
sin(x)=12
Step 3
Take the inverse sine of both sides of the equation to extract x from inside the sine.
x=arcsin(12)
Step 4
Simplify the right side.
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Step 4.1
The exact value of arcsin(12) is π6.
x=π6
x=π6
Step 5
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from π to find the solution in the second quadrant.
x=π-π6
Step 6
Simplify π-π6.
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Step 6.1
To write π as a fraction with a common denominator, multiply by 66.
x=π66-π6
Step 6.2
Combine fractions.
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Step 6.2.1
Combine π and 66.
x=π66-π6
Step 6.2.2
Combine the numerators over the common denominator.
x=π6-π6
x=π6-π6
Step 6.3
Simplify the numerator.
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Step 6.3.1
Move 6 to the left of π.
x=6π-π6
Step 6.3.2
Subtract π from 6π.
x=5π6
x=5π6
x=5π6
Step 7
Find the period of sin(x).
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Step 7.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 7.2
Replace b with 1 in the formula for period.
2π|1|
Step 7.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
2π1
Step 7.4
Divide 2π by 1.
2π
2π
Step 8
The period of the sin(x) function is 2π so values will repeat every 2π radians in both directions.
x=π6+2πn,5π6+2πn, for any integer n
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