Trigonometry Examples

cos(x)=35 , cot(x)=34
Step 1
To find the value of tan(x), use the fact that 1cot(x) then substitute in the known values.
tan(x)=1cot(x)=134
Step 2
Simplify the result.
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Step 2.1
Multiply the numerator by the reciprocal of the denominator.
tan(x)=1cot(x)=1(43)
Step 2.2
Multiply 43 by 1.
tan(x)=1cot(x)=43
tan(x)=1cot(x)=43
Step 3
To find the value of sin(x), use the fact that tan(x)=sin(x)cos(x) so sin(x)=tan(x)cos(x) then substitute in the known values.
sin(x)=tan(x)cos(x)=4335
Step 4
Simplify the result.
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Step 4.1
Cancel the common factor of 3.
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Step 4.1.1
Cancel the common factor.
sin(x)=tan(x)cos(x)=4335
Step 4.1.2
Rewrite the expression.
sin(x)=tan(x)cos(x)=415
sin(x)=tan(x)cos(x)=415
Step 4.2
Combine 4 and 15.
sin(x)=tan(x)cos(x)=45
sin(x)=tan(x)cos(x)=45
Step 5
To find the value of sec(x), use the fact that 1cos(x) then substitute in the known values.
sec(x)=1cos(x)=135
Step 6
Simplify the result.
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Step 6.1
Multiply the numerator by the reciprocal of the denominator.
sec(x)=1cos(x)=1(53)
Step 6.2
Multiply 53 by 1.
sec(x)=1cos(x)=53
sec(x)=1cos(x)=53
Step 7
To find the value of csc(x), use the fact that 1sin(x) then substitute in the known values.
csc(x)=1sin(x)=145
Step 8
Simplify the result.
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Step 8.1
Multiply the numerator by the reciprocal of the denominator.
csc(x)=1sin(x)=1(54)
Step 8.2
Multiply 54 by 1.
csc(x)=1sin(x)=54
csc(x)=1sin(x)=54
Step 9
The trig functions found are as follows:
sin(x)=45
cos(x)=35
tan(x)=43
cot(x)=34
sec(x)=53
csc(x)=54
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