Trigonometry Examples

csc(x)=53 , tan(x)=34
Step 1
To find the value of sin(x), use the fact that 1csc(x) then substitute in the known values.
sin(x)=1csc(x)=153
Step 2
Simplify the result.
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Step 2.1
Multiply the numerator by the reciprocal of the denominator.
sin(x)=1csc(x)=1(35)
Step 2.2
Multiply 35 by 1.
sin(x)=1csc(x)=35
sin(x)=1csc(x)=35
Step 3
To find the value of cos(x), use the fact that tan(x)=sin(x)cos(x) so cos(x)=sin(x)tan(x) then substitute in the known values.
cos(x)=sin(x)tan(x)=3534
Step 4
Simplify the result.
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Step 4.1
Multiply the numerator by the reciprocal of the denominator.
cos(x)=sin(x)tan(x)=3543
Step 4.2
Cancel the common factor of 3.
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Step 4.2.1
Cancel the common factor.
cos(x)=sin(x)tan(x)=3543
Step 4.2.2
Rewrite the expression.
cos(x)=sin(x)tan(x)=154
cos(x)=sin(x)tan(x)=154
Step 4.3
Combine 15 and 4.
cos(x)=sin(x)tan(x)=45
cos(x)=sin(x)tan(x)=45
Step 5
To find the value of cot(x), use the fact that 1tan(x) then substitute in the known values.
cot(x)=1tan(x)=134
Step 6
Simplify the result.
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Step 6.1
Multiply the numerator by the reciprocal of the denominator.
cot(x)=1tan(x)=1(43)
Step 6.2
Multiply 43 by 1.
cot(x)=1tan(x)=43
cot(x)=1tan(x)=43
Step 7
To find the value of sec(x), use the fact that 1cos(x) then substitute in the known values.
sec(x)=1cos(x)=145
Step 8
Simplify the result.
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Step 8.1
Multiply the numerator by the reciprocal of the denominator.
sec(x)=1cos(x)=1(54)
Step 8.2
Multiply 54 by 1.
sec(x)=1cos(x)=54
sec(x)=1cos(x)=54
Step 9
The trig functions found are as follows:
sin(x)=35
cos(x)=45
tan(x)=34
cot(x)=43
sec(x)=54
csc(x)=53
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