Trigonometry Examples
(2x3-x2-48x+15)÷(x-5)
Step 1
Place the numbers representing the divisor and the dividend into a division-like configuration.
5 | 2 | -1 | -48 | 15 |
Step 2
The first number in the dividend (2) is put into the first position of the result area (below the horizontal line).
5 | 2 | -1 | -48 | 15 |
2 |
Step 3
Multiply the newest entry in the result (2) by the divisor (5) and place the result of (10) under the next term in the dividend (-1).
5 | 2 | -1 | -48 | 15 |
10 | ||||
2 |
Step 4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
5 | 2 | -1 | -48 | 15 |
10 | ||||
2 | 9 |
Step 5
Multiply the newest entry in the result (9) by the divisor (5) and place the result of (45) under the next term in the dividend (-48).
5 | 2 | -1 | -48 | 15 |
10 | 45 | |||
2 | 9 |
Step 6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
5 | 2 | -1 | -48 | 15 |
10 | 45 | |||
2 | 9 | -3 |
Step 7
Multiply the newest entry in the result (-3) by the divisor (5) and place the result of (-15) under the next term in the dividend (15).
5 | 2 | -1 | -48 | 15 |
10 | 45 | -15 | ||
2 | 9 | -3 |
Step 8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
5 | 2 | -1 | -48 | 15 |
10 | 45 | -15 | ||
2 | 9 | -3 | 0 |
Step 9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
2x2+9x-3