Statistics Examples

P (A) = 0.9

$P (A) = 0.9$ ,

P (B) = 0.08

$P (B) = 0.08$

Step 1

When

A

$A$ and

B

$B$ are mutually exclusive events, the probability of

A

$A$ or

B

$B$ occurring is

P (A \cup B) = P (B \cup A) = P (A) + P (B)

$P (A \cup B) = P (B \cup A) = P (A) + P (B)$ , which is called the addition rule for mutually exclusive events

A

$A$ and

B

$B$ .

P (A \cup B) = P (B \cup A) = P (A) + P (B)

$P (A \cup B) = P (B \cup A) = P (A) + P (B)$

Step 2

Fill in the known values.

P (A \cup B) = P (B \cup A) = 0.9 + 0.08

$P (A \cup B) = P (B \cup A) = 0.9 + 0.08$

Step 3

Add

0.9

$0.9$ and

0.08

$0.08$ .

P (A \cup B) = P (B \cup A) = 0.98

$P (A \cup B) = P (B \cup A) = 0.98$

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