Statistics Examples

Find the Mean of the Frequency Table
ClassFrequency90-99480-89670-79460-69350-59240-491ClassFrequency909948089670794606935059240491
Step 1
Reorder the classes with their related frequencies (ƒ) in an ascending order (lowest number to highest), which is the most common.
ClassFrequency(f)40-49150-59260-69370-79480-89690-994ClassFrequency(f)404915059260693707948089690994
Step 2
Find the midpoint MM for each class.
ClassFrequency(f)Midpoint(M)40-49144.550-59254.560-69364.570-79474.580-89684.590-99494.5ClassFrequency(f)Midpoint(M)4049144.55059254.56069364.57079474.58089684.59099494.5
Step 3
Multiply the frequency of each class by the class midpoint.
ClassFrequency(f)Midpoint(M)fM40-49144.5144.550-59254.5254.560-69364.5364.570-79474.5474.580-89684.5684.590-99494.5494.5ClassFrequency(f)Midpoint(M)fM4049144.5144.55059254.5254.56069364.5364.57079474.5474.58089684.5684.59099494.5494.5
Step 4
Simplify the fMfM column.
ClassFrequency(f)Midpoint(M)fM40-49144.544.550-59254.510960-69364.5193.570-79474.529880-89684.550790-99494.5378ClassFrequency(f)Midpoint(M)fM4049144.544.55059254.51096069364.5193.57079474.52988089684.55079099494.5378
Step 5
Add the values in the fMfM column.
44.5+109+193.5+298+507+378=153044.5+109+193.5+298+507+378=1530
Step 6
Add the values in the frequency column.
n=1+2+3+4+6+4=20n=1+2+3+4+6+4=20
Step 7
The mean (mu) is the sum of fMfM divided by nn, which is the sum of frequencies.
μ=fMfμ=fMf
Step 8
The mean is the sum of the product of the midpoints and frequencies divided by the total of frequencies.
μ=153020μ=153020
Step 9
Simplify the right side of μ=153020μ=153020.
76.576.5
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