Statistics Examples
ClassFrequency90−99480−89670−79460−69350−59240−491
Step 1
Reorder the classes with their related frequencies (ƒ) in an ascending order (lowest number to highest), which is the most common.
ClassFrequency(f)40−49150−59260−69370−79480−89690−994
Step 2
Find the midpoint M for each class.
ClassFrequency(f)Midpoint(M)40−49144.550−59254.560−69364.570−79474.580−89684.590−99494.5
Step 3
Multiply the frequency of each class by the class midpoint.
ClassFrequency(f)Midpoint(M)f⋅M40−49144.51⋅44.550−59254.52⋅54.560−69364.53⋅64.570−79474.54⋅74.580−89684.56⋅84.590−99494.54⋅94.5
Step 4
Simplify the f⋅M column.
ClassFrequency(f)Midpoint(M)f⋅M40−49144.544.550−59254.510960−69364.5193.570−79474.529880−89684.550790−99494.5378
Step 5
Add the values in the f⋅M column.
44.5+109+193.5+298+507+378=1530
Step 6
Add the values in the frequency column.
n=1+2+3+4+6+4=20
Step 7
The mean (mu) is the sum of f⋅M divided by n, which is the sum of frequencies.
μ=∑f⋅M∑f
Step 8
The mean is the sum of the product of the midpoints and frequencies divided by the total of frequencies.
μ=153020
Step 9
Simplify the right side of μ=153020.
76.5