Examples

Determine if the Expression is a Factor Using Synthetic Division
2x2+x-3 , x-1
Step 1
Divide 2x2+x-3x-1 using synthetic division and check if the remainder is equal to 0. If the remainder is equal to 0, it means that x-1 is a factor for 2x2+x-3. If the remainder is not equal to 0, it means that x-1 is not a factor for 2x2+x-3.
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Step 1.1
Place the numbers representing the divisor and the dividend into a division-like configuration.
121-3
  
Step 1.2
The first number in the dividend (2) is put into the first position of the result area (below the horizontal line).
121-3
  
2
Step 1.3
Multiply the newest entry in the result (2) by the divisor (1) and place the result of (2) under the next term in the dividend (1).
121-3
 2 
2
Step 1.4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
121-3
 2 
23
Step 1.5
Multiply the newest entry in the result (3) by the divisor (1) and place the result of (3) under the next term in the dividend (-3).
121-3
 23
23
Step 1.6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
121-3
 23
230
Step 1.7
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
(2)x+3
Step 1.8
Simplify the quotient polynomial.
2x+3
2x+3
Step 2
The remainder from dividing 2x2+x-3x-1 is 0, which means that x-1 is a factor for 2x2+x-3.
x-1 is a factor for 2x2+x-3
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 [x2  12  π  xdx ] 
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