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Examples

f (x) = x + 7 (x - 2)

$f (x) = x + 7 (x - 2)$

Step 1

Write

f (x) = x + 7 (x - 2)

$f (x) = x + 7 (x - 2)$ as an equation.

y = x + 7 (x - 2)

$y = x + 7 (x - 2)$

Step 2

Simplify

x + 7 (x - 2)

$x + 7 (x - 2)$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

y = x + 7 x + 7 \cdot - 2

$y = x + 7 x + 7 \cdot - 2$

Step 2.1.2

Multiply

7

$7$ by

- 2

$- 2$ .

y = x + 7 x - 14

$y = x + 7 x - 14$

y = x + 7 x - 14

$y = x + 7 x - 14$

Step 2.2

Add

x

$x$ and

7 x

$7 x$ .

y = 8 x - 14

$y = 8 x - 14$

y = 8 x - 14

$y = 8 x - 14$

Step 3

Choose any value for

x

$x$ that is in the domain to plug into the equation.

Step 4

Choose

0

$0$ to substitute in for

x

$x$ to find the ordered pair.

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Step 4.1

Remove parentheses.

y = 8 (0) - 14

$y = 8 (0) - 14$

Step 4.2

Simplify

8 (0) - 14

$8 (0) - 14$ .

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Step 4.2.1

Multiply

8

$8$ by

0

$0$ .

y = 0 - 14

$y = 0 - 14$

Step 4.2.2

Subtract

14

$14$ from

0

$0$ .

y = - 14

$y = - 14$

y = - 14

$y = - 14$

Step 4.3

Use the

x

$x$ and

y

$y$ values to form the ordered pair.

(0, - 14)

$(0, - 14)$

(0, - 14)

$(0, - 14)$

Step 5

Choose

1

$1$ to substitute in for

x

$x$ to find the ordered pair.

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Step 5.1

Remove parentheses.

y = 8 (1) - 14

$y = 8 (1) - 14$

Step 5.2

Simplify

8 (1) - 14

$8 (1) - 14$ .

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Step 5.2.1

Multiply

8

$8$ by

1

$1$ .

y = 8 - 14

$y = 8 - 14$

Step 5.2.2

Subtract

14

$14$ from

8

$8$ .

y = - 6

$y = - 6$

y = - 6

$y = - 6$

Step 5.3

Use the

x

$x$ and

y

$y$ values to form the ordered pair.

(1, - 6)

$(1, - 6)$

(1, - 6)

$(1, - 6)$

Step 6

Choose

2

$2$ to substitute in for

x

$x$ to find the ordered pair.

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Step 6.1

Remove parentheses.

y = 8 (2) - 14

$y = 8 (2) - 14$

Step 6.2

Simplify

8 (2) - 14

$8 (2) - 14$ .

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Step 6.2.1

Multiply

8

$8$ by

2

$2$ .

y = 16 - 14

$y = 16 - 14$

Step 6.2.2

Subtract

14

$14$ from

16

$16$ .

y = 2

$y = 2$

y = 2

$y = 2$

Step 6.3

Use the

x

$x$ and

y

$y$ values to form the ordered pair.

(2, 2)

$(2, 2)$

(2, 2)

$(2, 2)$

Step 7

These are three possible solutions to the equation.

(0, - 14), (1, - 6), (2, 2)

$(0, - 14), (1, - 6), (2, 2)$

Step 8

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$