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Precalculus Examples

(1, 2)

$(1, 2)$ ,

(1, - 1)

$(1, - 1)$

Step 1

Since

x = 1

$x = 1$ produces

y = 2

$y = 2$ and

y = - 1

$y = - 1$ , the relation

(1, 2), (1, - 1)

$(1, 2), (1, - 1)$ is not a function.

The relation is not a function.

Step 2

The relation

(1, 2), (1, - 1)

$(1, 2), (1, - 1)$ is not a function, so there is no inverse can be found.

No inverse can be found

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$