Precalculus Examples

$x^{2} - 5 x - 6 = 9$

Step 1

Move all terms to the left side of the equation and simplify.

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Step 1.1

Subtract $9$ from both sides of the equation.

$x^{2} - 5 x - 6 - 9 = 0$

Step 1.2

Subtract $9$ from $- 6$ .

$x^{2} - 5 x - 15 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 1$ , $b = - 5$ , $c = - 15$

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