Precalculus Examples

2=|3x|
Step 1
Rewrite the equation as |3x|=2.
|3x|=2
Step 2
Remove the absolute value term. This creates a ± on the right side of the equation because |x|=±x.
3x=±2
Step 3
The complete solution is the result of both the positive and negative portions of the solution.
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Step 3.1
First, use the positive value of the ± to find the first solution.
3x=2
Step 3.2
Divide each term in 3x=2 by 3 and simplify.
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Step 3.2.1
Divide each term in 3x=2 by 3.
3x3=23
Step 3.2.2
Simplify the left side.
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Step 3.2.2.1
Cancel the common factor of 3.
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Step 3.2.2.1.1
Cancel the common factor.
3x3=23
Step 3.2.2.1.2
Divide x by 1.
x=23
x=23
x=23
x=23
Step 3.3
Next, use the negative value of the ± to find the second solution.
3x=-2
Step 3.4
Divide each term in 3x=-2 by 3 and simplify.
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Step 3.4.1
Divide each term in 3x=-2 by 3.
3x3=-23
Step 3.4.2
Simplify the left side.
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Step 3.4.2.1
Cancel the common factor of 3.
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Step 3.4.2.1.1
Cancel the common factor.
3x3=-23
Step 3.4.2.1.2
Divide x by 1.
x=-23
x=-23
x=-23
Step 3.4.3
Simplify the right side.
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Step 3.4.3.1
Move the negative in front of the fraction.
x=-23
x=-23
x=-23
Step 3.5
The complete solution is the result of both the positive and negative portions of the solution.
x=23,-23
x=23,-23
Step 4
The result can be shown in multiple forms.
Exact Form:
x=23,-23
Decimal Form:
x=0.6,-0.6
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 [x2  12  π  xdx ] 
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