Precalculus Examples

(6, 8)

$(6, 8)$ ,

(- 9, - 3)

$(- 9, - 3)$

Step 1

Use the distance formula to determine the distance between the two points.

Distance = \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2}}

$Distance = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$

Step 2

Substitute the actual values of the points into the distance formula.

\sqrt{{((- 9) - 6)}^{2} + {((- 3) - 8)}^{2}}

$\sqrt{{((- 9) - 6)}^{2} + {((- 3) - 8)}^{2}}$

Step 3

Simplify.

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Step 3.1

Subtract

6

$6$ from

- 9

$- 9$ .

\sqrt{{(- 15)}^{2} + {((- 3) - 8)}^{2}}

$\sqrt{{(- 15)}^{2} + {((- 3) - 8)}^{2}}$

Step 3.2

Raise

- 15

$- 15$ to the power of

2

$2$ .

\sqrt{225 + {((- 3) - 8)}^{2}}

$\sqrt{225 + {((- 3) - 8)}^{2}}$

Step 3.3

Subtract

8

$8$ from

- 3

$- 3$ .

\sqrt{225 + {(- 11)}^{2}}

$\sqrt{225 + {(- 11)}^{2}}$

Step 3.4

Raise

- 11

$- 11$ to the power of

2

$2$ .

\sqrt{225 + 121}

$\sqrt{225 + 121}$

Step 3.5

Add

225

$225$ and

121

$121$ .

\sqrt{346}

$\sqrt{346}$

\sqrt{346}

$\sqrt{346}$

Step 4

The result can be shown in multiple forms.

Exact Form:

\sqrt{346}

$\sqrt{346}$

Decimal Form:

18.60107523 \dots

$18.60107523 \dots$

Step 5

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