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Precalculus Examples

f (x) = 2 x^{2} + 2

$f (x) = 2 x^{2} + 2$ ,

f (2)

$f (2)$

Step 1

Replace the variable

x

$x$ with

2

$2$ in the expression.

f (2) = 2 {(2)}^{2} + 2

$f (2) = 2 {(2)}^{2} + 2$

Step 2

Simplify

2 {(2)}^{2} + 2

$2 {(2)}^{2} + 2$ .

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Step 2.1

Remove parentheses.

2 {(2)}^{2} + 2

$2 {(2)}^{2} + 2$

Step 2.2

Simplify each term.

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Step 2.2.1

Multiply

2

$2$ by

{(2)}^{2}

${(2)}^{2}$ by adding the exponents.

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Step 2.2.1.1

Multiply

2

$2$ by

{(2)}^{2}

${(2)}^{2}$ .

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Step 2.2.1.1.1

Raise

2

$2$ to the power of

1

$1$ .

2^{1} {(2)}^{2} + 2

$2^{1} {(2)}^{2} + 2$

Step 2.2.1.1.2

Use the power rule

a^{m} a^{n} = a^{m + n}

$a^{m} a^{n} = a^{m + n}$ to combine exponents.

2^{1 + 2} + 2

$2^{1 + 2} + 2$

2^{1 + 2} + 2

$2^{1 + 2} + 2$

Step 2.2.1.2

Add

1

$1$ and

2

$2$ .

2^{3} + 2

$2^{3} + 2$

2^{3} + 2

$2^{3} + 2$

Step 2.2.2

Raise

2

$2$ to the power of

3

$3$ .

8 + 2

$8 + 2$

8 + 2

$8 + 2$

Step 2.3

Add

8

$8$ and

2

$2$ .

10

$10$

10

$10$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$