Precalculus Examples

$x - [\begin{array}{c} 1 & - 12 & 0 \\ 10 & 9 & 1 \end{array}] = [\begin{array}{c} - 2 & 12 & 2 \\ - 8 & \frac{3}{2} & 4 \end{array}]$

Step 1

Move all terms not containing a variable to the right side.

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Step 1.1

Add $[\begin{array}{c} 1 & - 12 & 0 \\ 10 & 9 & 1 \end{array}]$ to both sides of the equation.

$x = [\begin{array}{c} - 2 & 12 & 2 \\ - 8 & \frac{3}{2} & 4 \end{array}] + [\begin{array}{c} 1 & - 12 & 0 \\ 10 & 9 & 1 \end{array}]$

Step 2

Simplify the right side.

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Step 2.1

Add the corresponding elements.

$x = [\begin{array}{c} - 2 + 1 & 12 - 12 & 2 + 0 \\ - 8 + 10 & \frac{3}{2} + 9 & 4 + 1 \end{array}]$

Step 2.2

Simplify each element.

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Step 2.2.1

Add $- 2$ and $1$ .

$x = [\begin{array}{c} - 1 & 12 - 12 & 2 + 0 \\ - 8 + 10 & \frac{3}{2} + 9 & 4 + 1 \end{array}]$

Step 2.2.2

Subtract $12$ from $12$ .

$x = [\begin{array}{c} - 1 & 0 & 2 + 0 \\ - 8 + 10 & \frac{3}{2} + 9 & 4 + 1 \end{array}]$

Step 2.2.3

Add $2$ and $0$ .

$x = [\begin{array}{c} - 1 & 0 & 2 \\ - 8 + 10 & \frac{3}{2} + 9 & 4 + 1 \end{array}]$

Step 2.2.4

Add $- 8$ and $10$ .

$x = [\begin{array}{c} - 1 & 0 & 2 \\ 2 & \frac{3}{2} + 9 & 4 + 1 \end{array}]$

Step 2.2.5

To write $9$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x = [\begin{array}{c} - 1 & 0 & 2 \\ 2 & \frac{3}{2} + 9 \cdot \frac{2}{2} & 4 + 1 \end{array}]$

Step 2.2.6

Combine $9$ and $\frac{2}{2}$ .

$x = [\begin{array}{c} - 1 & 0 & 2 \\ 2 & \frac{3}{2} + \frac{9 \cdot 2}{2} & 4 + 1 \end{array}]$

Step 2.2.7

Combine the numerators over the common denominator.

$x = [\begin{array}{c} - 1 & 0 & 2 \\ 2 & \frac{3 + 9 \cdot 2}{2} & 4 + 1 \end{array}]$

Step 2.2.8

Simplify the numerator.

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Step 2.2.8.1

Multiply $9$ by $2$ .

$x = [\begin{array}{c} - 1 & 0 & 2 \\ 2 & \frac{3 + 18}{2} & 4 + 1 \end{array}]$

Step 2.2.8.2

Add $3$ and $18$ .

$x = [\begin{array}{c} - 1 & 0 & 2 \\ 2 & \frac{21}{2} & 4 + 1 \end{array}]$

Step 2.2.9

Add $4$ and $1$ .

$x = [\begin{array}{c} - 1 & 0 & 2 \\ 2 & \frac{21}{2} & 5 \end{array}]$

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