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Precalculus Examples

4

$4$ ,

(2, - 4)

$(2, - 4)$

Step 1

Find the value of

b

$b$ using the formula for the equation of a line.

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Step 1.1

Use the formula for the equation of a line to find

b

$b$ .

y = m x + b

$y = m x + b$

Step 1.2

Substitute the value of

m

$m$ into the equation.

y = (4) \cdot x + b

$y = (4) \cdot x + b$

Step 1.3

Substitute the value of

x

$x$ into the equation.

y = (4) \cdot (2) + b

$y = (4) \cdot (2) + b$

Step 1.4

Substitute the value of

y

$y$ into the equation.

- 4 = (4) \cdot (2) + b

$- 4 = (4) \cdot (2) + b$

Step 1.5

Find the value of

b

$b$ .

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Step 1.5.1

Rewrite the equation as

(4) \cdot (2) + b = - 4

$(4) \cdot (2) + b = - 4$ .

(4) \cdot (2) + b = - 4

$(4) \cdot (2) + b = - 4$

Step 1.5.2

Multiply

4

$4$ by

2

$2$ .

8 + b = - 4

$8 + b = - 4$

Step 1.5.3

Move all terms not containing

b

$b$ to the right side of the equation.

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Step 1.5.3.1

Subtract

8

$8$ from both sides of the equation.

b = - 4 - 8

$b = - 4 - 8$

Step 1.5.3.2

Subtract

8

$8$ from

- 4

$- 4$ .

b = - 12

$b = - 12$

b = - 12

$b = - 12$

b = - 12

$b = - 12$

b = - 12

$b = - 12$

Step 2

Now that the values of

m

$m$ (slope) and

b

$b$ (y-intercept) are known, substitute them into

y = m x + b

$y = m x + b$ to find the equation of the line.

y = 4 x - 12

$y = 4 x - 12$

Step 3

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$