Precalculus Examples
f(x)=4x3 , x=0
Step 1
Set up the long division problem to evaluate the function at 0.
4x3x-(0)
Step 2
Step 2.1
Place the numbers representing the divisor and the dividend into a division-like configuration.
0 | 4 | 0 | 0 | 0 |
Step 2.2
The first number in the dividend (4) is put into the first position of the result area (below the horizontal line).
0 | 4 | 0 | 0 | 0 |
4 |
Step 2.3
Multiply the newest entry in the result (4) by the divisor (0) and place the result of (0) under the next term in the dividend (0).
0 | 4 | 0 | 0 | 0 |
0 | ||||
4 |
Step 2.4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
0 | 4 | 0 | 0 | 0 |
0 | ||||
4 | 0 |
Step 2.5
Multiply the newest entry in the result (0) by the divisor (0) and place the result of (0) under the next term in the dividend (0).
0 | 4 | 0 | 0 | 0 |
0 | 0 | |||
4 | 0 |
Step 2.6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
0 | 4 | 0 | 0 | 0 |
0 | 0 | |||
4 | 0 | 0 |
Step 2.7
Multiply the newest entry in the result (0) by the divisor (0) and place the result of (0) under the next term in the dividend (0).
0 | 4 | 0 | 0 | 0 |
0 | 0 | 0 | ||
4 | 0 | 0 |
Step 2.8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
0 | 4 | 0 | 0 | 0 |
0 | 0 | 0 | ||
4 | 0 | 0 | 0 |
Step 2.9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
4x2+0x+0
Step 2.10
Simplify the quotient polynomial.
4x2
4x2
Step 3
The remainder of the synthetic division is the result based on the remainder theorem.
0
Step 4
Since the remainder is equal to zero, x=0 is a factor.
x=0 is a factor
Step 5