Precalculus Examples

Find All Integers k Such That the Trinomial Can Be Factored
9x2-kx+1
Step 1
Find the values of a and c in the trinomial 9x2-kx+1 with the format ax2+kx+c.
a=9
c=1
Step 2
For the trinomial 9x2-kx+1, find the value of ac.
ac=9
Step 3
To find all possible values of k, first find the factors of ac 9. Once a factor is found, add it to its corresponding factor to get a possible value for k. The factors for 9 are all numbers between -9 and 9, which divide 9 evenly.
Check numbers between -9 and 9
Step 4
Calculate the factors of 9. Add corresponding factors to get all possible k values.
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Step 4.1
Since 9 divided by -9 is the whole number -1, -9 and -1 are factors of 9.
-9 and -1 are factors
Step 4.2
Add the factors -9 and -1 together. Add -10 to the list of possible k values.
k=-10
Step 4.3
Since 9 divided by -3 is the whole number -3, -3 and -3 are factors of 9.
-3 and -3 are factors
Step 4.4
Add the factors -3 and -3 together. Add -6 to the list of possible k values.
k=-10,-6
Step 4.5
Since 9 divided by 1 is the whole number 9, 1 and 9 are factors of 9.
1 and 9 are factors
Step 4.6
Add the factors 1 and 9 together. Add 10 to the list of possible k values.
k=-10,-6,10
Step 4.7
Since 9 divided by 3 is the whole number 3, 3 and 3 are factors of 9.
3 and 3 are factors
Step 4.8
Add the factors 3 and 3 together. Add 6 to the list of possible k values.
k=-10,-6,10,6
k=-10,-6,10,6
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 [x2  12  π  xdx ] 
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