Precalculus Examples

{(x + 2)}^{2}

${(x + 2)}^{2}$

Step 1

Use the binomial expansion theorem to find each term. The binomial theorem states

{(a + b)}^{n} = \sum_{k = 0}^{n} n C k \cdot (a^{n - k} b^{k})

${(a + b)}^{n} = \sum_{k = 0}^{n} n C k \cdot (a^{n - k} b^{k})$ .

\sum_{k = 0}^{2} \frac{2!}{(2 - k)! k!} \cdot {(x)}^{2 - k} \cdot {(2)}^{k}

$\sum_{k = 0}^{2} \frac{2!}{(2 - k)! k!} \cdot {(x)}^{2 - k} \cdot {(2)}^{k}$

Step 2

Expand the summation.

\frac{2!}{(2 - 0)! 0!} {(x)}^{2 - 0} \cdot {(2)}^{0} + \frac{2!}{(2 - 1)! 1!} {(x)}^{2 - 1} \cdot {(2)}^{1} + \frac{2!}{(2 - 2)! 2!} {(x)}^{2 - 2} \cdot {(2)}^{2}

$\frac{2!}{(2 - 0)! 0!} {(x)}^{2 - 0} \cdot {(2)}^{0} + \frac{2!}{(2 - 1)! 1!} {(x)}^{2 - 1} \cdot {(2)}^{1} + \frac{2!}{(2 - 2)! 2!} {(x)}^{2 - 2} \cdot {(2)}^{2}$

Step 3

Simplify the exponents for each term of the expansion.

1 \cdot {(x)}^{2} \cdot {(2)}^{0} + 2 \cdot {(x)}^{1} \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}

$1 \cdot {(x)}^{2} \cdot {(2)}^{0} + 2 \cdot {(x)}^{1} \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}$

Step 4

Simplify each term.

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Step 4.1

Multiply

{(x)}^{2}

${(x)}^{2}$ by

1

$1$ .

{(x)}^{2} \cdot {(2)}^{0} + 2 \cdot {(x)}^{1} \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}

${(x)}^{2} \cdot {(2)}^{0} + 2 \cdot {(x)}^{1} \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}$

Step 4.2

Anything raised to

0

$0$ is

1

$1$ .

x^{2} \cdot 1 + 2 \cdot {(x)}^{1} \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}

$x^{2} \cdot 1 + 2 \cdot {(x)}^{1} \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}$

Step 4.3

Multiply

x^{2}

$x^{2}$ by

1

$1$ .

x^{2} + 2 \cdot {(x)}^{1} \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}

$x^{2} + 2 \cdot {(x)}^{1} \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}$

Step 4.4

Simplify.

x^{2} + 2 \cdot x \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}

$x^{2} + 2 \cdot x \cdot {(2)}^{1} + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}$

Step 4.5

Evaluate the exponent.

x^{2} + 2 x \cdot 2 + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}

$x^{2} + 2 x \cdot 2 + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}$

Step 4.6

Multiply

2

$2$ by

2

$2$ .

x^{2} + 4 x + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}

$x^{2} + 4 x + 1 \cdot {(x)}^{0} \cdot {(2)}^{2}$

Step 4.7

Multiply

{(x)}^{0}

${(x)}^{0}$ by

1

$1$ .

x^{2} + 4 x + {(x)}^{0} \cdot {(2)}^{2}

$x^{2} + 4 x + {(x)}^{0} \cdot {(2)}^{2}$

Step 4.8

Anything raised to

0

$0$ is

1

$1$ .

x^{2} + 4 x + 1 \cdot {(2)}^{2}

$x^{2} + 4 x + 1 \cdot {(2)}^{2}$

Step 4.9

Multiply

{(2)}^{2}

${(2)}^{2}$ by

1

$1$ .

x^{2} + 4 x + {(2)}^{2}

$x^{2} + 4 x + {(2)}^{2}$

Step 4.10

Raise

2

$2$ to the power of

2

$2$ .

x^{2} + 4 x + 4

$x^{2} + 4 x + 4$

x^{2} + 4 x + 4

$x^{2} + 4 x + 4$

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