Precalculus Examples

Find the Circle Through (-6,6) with Center (0,0)
(0,0) , (-6,6)
Step 1
Find the radius r for the circle. The radius is any line segment from the center of the circle to any point on its circumference. In this case, r is the distance between (0,0) and (-6,6).
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Step 1.1
Use the distance formula to determine the distance between the two points.
Distance=(x2-x1)2+(y2-y1)2
Step 1.2
Substitute the actual values of the points into the distance formula.
r=((-6)-0)2+(6-0)2
Step 1.3
Simplify.
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Step 1.3.1
Subtract 0 from -6.
r=(-6)2+(6-0)2
Step 1.3.2
Raise -6 to the power of 2.
r=36+(6-0)2
Step 1.3.3
Subtract 0 from 6.
r=36+62
Step 1.3.4
Raise 6 to the power of 2.
r=36+36
Step 1.3.5
Add 36 and 36.
r=72
Step 1.3.6
Rewrite 72 as 622.
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Step 1.3.6.1
Factor 36 out of 72.
r=36(2)
Step 1.3.6.2
Rewrite 36 as 62.
r=622
r=622
Step 1.3.7
Pull terms out from under the radical.
r=62
r=62
r=62
Step 2
(x-h)2+(y-k)2=r2 is the equation form for a circle with r radius and (h,k) as the center point. In this case, r=62 and the center point is (0,0). The equation for the circle is (x-(0))2+(y-(0))2=(62)2.
(x-(0))2+(y-(0))2=(62)2
Step 3
The circle equation is (x-0)2+(y-0)2=72.
(x-0)2+(y-0)2=72
Step 4
Simplify the circle equation.
x2+y2=72
Step 5
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