Precalculus Examples
x2+5xx-4x2+5xx−4
Step 1
Step 1.1
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of 00.
xx | - | 44 | x2x2 | + | 5x5x | + | 00 |
Step 1.2
Divide the highest order term in the dividend x2x2 by the highest order term in divisor xx.
xx | |||||||||
xx | - | 44 | x2x2 | + | 5x5x | + | 00 |
Step 1.3
Multiply the new quotient term by the divisor.
xx | |||||||||
xx | - | 44 | x2x2 | + | 5x5x | + | 00 | ||
+ | x2x2 | - | 4x4x |
Step 1.4
The expression needs to be subtracted from the dividend, so change all the signs in x2-4xx2−4x
xx | |||||||||
xx | - | 44 | x2x2 | + | 5x5x | + | 00 | ||
- | x2x2 | + | 4x4x |
Step 1.5
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
xx | |||||||||
xx | - | 44 | x2x2 | + | 5x5x | + | 00 | ||
- | x2x2 | + | 4x4x | ||||||
+ | 9x9x |
Step 1.6
Pull the next terms from the original dividend down into the current dividend.
xx | |||||||||
xx | - | 44 | x2x2 | + | 5x5x | + | 00 | ||
- | x2x2 | + | 4x4x | ||||||
+ | 9x9x | + | 00 |
Step 1.7
Divide the highest order term in the dividend 9x9x by the highest order term in divisor xx.
xx | + | 99 | |||||||
xx | - | 44 | x2x2 | + | 5x5x | + | 00 | ||
- | x2x2 | + | 4x4x | ||||||
+ | 9x9x | + | 00 |
Step 1.8
Multiply the new quotient term by the divisor.
xx | + | 99 | |||||||
xx | - | 44 | x2 | + | 5x | + | 0 | ||
- | x2 | + | 4x | ||||||
+ | 9x | + | 0 | ||||||
+ | 9x | - | 36 |
Step 1.9
The expression needs to be subtracted from the dividend, so change all the signs in 9x-36
x | + | 9 | |||||||
x | - | 4 | x2 | + | 5x | + | 0 | ||
- | x2 | + | 4x | ||||||
+ | 9x | + | 0 | ||||||
- | 9x | + | 36 |
Step 1.10
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
x | + | 9 | |||||||
x | - | 4 | x2 | + | 5x | + | 0 | ||
- | x2 | + | 4x | ||||||
+ | 9x | + | 0 | ||||||
- | 9x | + | 36 | ||||||
+ | 36 |
Step 1.11
The final answer is the quotient plus the remainder over the divisor.
x+9+36x-4
x+9+36x-4
Step 2
Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.
36