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Precalculus Examples

| 3 y | + 3 = 3

$| 3 y | + 3 = 3$

Step 1

Move all terms not containing

| 3 y |

$| 3 y |$ to the right side of the equation.

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Step 1.1

Subtract

3

$3$ from both sides of the equation.

| 3 y | = 3 - 3

$| 3 y | = 3 - 3$

Step 1.2

Subtract

3

$3$ from

3

$3$ .

| 3 y | = 0

$| 3 y | = 0$

| 3 y | = 0

$| 3 y | = 0$

Step 2

Remove the absolute value term. This creates a

\pm

$\pm$ on the right side of the equation because

| x | = \pm x

$| x | = \pm x$ .

3 y = \pm 0

$3 y = \pm 0$

Step 3

Plus or minus

0

$0$ is

0

$0$ .

3 y = 0

$3 y = 0$

Step 4

Divide each term in

3 y = 0

$3 y = 0$ by

3

$3$ and simplify.

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Step 4.1

Divide each term in

3 y = 0

$3 y = 0$ by

3

$3$ .

\frac{3 y}{3} = \frac{0}{3}

$\frac{3 y}{3} = \frac{0}{3}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of

3

$3$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{3 y}{3} = \frac{0}{3}$

Step 4.2.1.2

Divide

$y$ by

$1$ .

$y = \frac{0}{3}$

$y = \frac{0}{3}$

$y = \frac{0}{3}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide

$0$ by

$3$ .

$y = 0$

$y = 0$

$y = 0$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$